文章作者:Tyan
博客:noahsnail.com | CSDN | 简书
1. Description
Arithmetic Subarrays2. Solution
解析:Version 1,根据左右索引,对数组切片,然后排序,判断其是否是算术(等差)子数组。
- Version 1
class Solution:
def checkArithmeticSubarrays(self, nums: List[int], l: List[int], r: List[int]) -> List[bool]:
m = len(l)
result = []
for i in range(m):
left = l[i]
right = r[i]
temp = nums[left:right+1]
temp.sort()
flag = True
for j in range(2, len(temp)):
if temp[j] - temp[j-1] != temp[j-1] - temp[j-2]:
flag = False
break
result.append(flag)
return result
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