给定一个字符串,你需要反转字符串中每个单词的字符顺序,同时仍保留空格和单词的初始顺序。
示例 1:
输入: "Let's take LeetCode contest"
输出: "s'teL ekat edoCteeL tsetnoc"
注意:在字符串中,每个单词由单个空格分隔,并且字符串中不会有任何额外的空格。
class Solution {
public String reverseWords(String s) {
StringBuilder builder = new StringBuilder();
String[] array = s.split(" ");
int length = array.length;
if(length > 0){
for(int i = 0; i < length; i++){
builder.append(reverse(array[i]));
builder.append(" ");
}
}
return builder.toString().trim();
}
private String reverse(String str){
StringBuilder builder = new StringBuilder();
if(str != null && str != ""){
int length = str.length();
for(int i = 0; i < length; i++){
builder.append(str.charAt(length - 1 -i));
}
}
return builder.toString();
}
}
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