Python学习（2）

3 Screenshot_2016-12-24-23-12-11.jpeg

学习编程这件事，很想很想，却一直不知道如何开始。更准确地说，不敢于去尝试开始。昨天，听完老师的课，终于自己动手写了一页比较长的代码，而且得到了老师的认可，好开心！老师给的练习题是求解一个列表的最小值、最大值、元素数和平均值：

Your task is to process a sequence of integer numbers to determine the following statistic:

• minimum value
• maximum value
• number of elements in the sequence
• average value

For example:[6,9,15,-2,92,11]

正确的输出结果是这样的：

• minimum value = -2

• maximum value = 92
• number of elements in the sequence = 6
• average value = 21.833333

但自己输出的平均值只能是21.0或者21，后面的几位小数出不来。请教了老师，说是和后面马上要学的数据类型有关系。按老师的方法乘了一个1.0，就得到了正确的结果。自己的代码如下：

def MinResult(grades):
    n=0
    MinValue=grades[1]
    while n < len(grades):
        if grades[n]<MinValue:
            MinValue=grades[n]
        n=n+1
    return MinValue

def PrintMinResult(grades):
    print (MinResult(grades))

def MaxResult(grades):
    n=0
    MaxValue=grades[1]
    while n < len(grades):
        if grades[n]>MaxValue:
            MaxValue=grades[n]
        n=n+1
    return MaxValue

def PrintMaxResult(grades):
    print (MaxResult(grades))

def PrintNumberOfElements(grades):
    print(len(grades))

def AverageValue(grades):
    n=0
    sum=0
    while n<len(grades):
        sum=sum+grades[n]
        n=n+1
    AverageResult=1.0*sum/len(grades)
    return round(AverageResult,6)
    
def PrintAverageValue(grades):
    print(AverageValue(grades))
    
grades_A=[6,9,15,-2,92,11]
PrintMinResult(grades_A)
PrintMaxResult(grades_A)
PrintNumberOfElements(grades_A)
PrintAverageValue(grades_A)

小确幸。