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383. Ransom Note

383. Ransom Note

作者: exialym | 来源:发表于2016-09-21 22:51 被阅读16次

    Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false.

    Each letter in the magazine string can only be used once in your ransom note.

    Note:
    You may assume that both strings contain only lowercase letters.

    canConstruct("a", "b") -> false
    canConstruct("aa", "ab") -> false
    canConstruct("aa", "aab") -> true

    使用变查找边替换的方法

    var canConstruct = function(ransomNote, magazine) {
        var num = ransomNote.length;
        for (var i = 0; i<num; i++) {
            var index = magazine.indexOf(ransomNote[i]);
            if (index===-1) {
                return false;
            } else {
                magazine = magazine.replace(ransomNote[i],'');
            }
        }
        return true;
    };
    

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