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第六章循环控制语句

第六章循环控制语句

作者: 小风xf | 来源:发表于2018-11-18 10:49 被阅读0次

    何时退出一个循环

    #include <stdio.h>

    void main()

    {

        int n = 5;

        while (n < 7 ) {

            printf("n = %d \n ",n);

            n ++ ;

            printf("now n = %d \n",n);

        }

        printf("the loop has finished \n.  ");

    }

    无限循环语句

    #include <stdio.h>

    void main()

    {

        int n = 0;

        while (n < 3 )

            printf("n = %d \n ",n);

            n ++ ;

            printf("now n = %d \n",n);

        printf("the loop has finished \n.  ");

    }

    浮点数比较

    #include <math.h>

    #include <stdio.h>

    int main()

    {

        const double Answer = 3.14159;

        double response ;

        printf("what is the value of pi ? \n");

        scanf( " %lf", &response);

        while (fabs(response - Answer)> 0.0001)

        {

            printf("try again !\n");

            scanf( " %lf", &response);

        }

        printf("close enough\n");

    }

    c中的真和假

    #include <stdio.h>

    void main()

    {

        int ture_val,false_val;

        ture_val = (10>2);

        false_val = (10 == 2);

        printf("true = %d , false = %d ",ture_val,false_val);

    }

    那些值为真

    #include <stdio.h>

    void main()

    {

        int  n  =3 ;

        while (n ) {

            printf("%2d is true \n ",n--);

        }

        printf("%2d is false \n",n);

        n = -3 ;

        while (n) {

            printf("%2d is true\n",n++);

        }

          printf("%2d is false \n",n);

    }

    #include <stdio.h>

    void main()

    {

        long num ;

        long sum = 0l;

        int status ;

        printf("please enter next integer ( q to quit );");

        printf("(qto quit :");

        status =scanf("%ld",&num);

        while(status ==  1  )// while (status ==  1  )会导致无限循环

        {

            sum +=num ;

            printf("please enter next integer ( q to quit );");

            status =scanf("%ld",&num);

        }

        printf("those integers sum to %ld \n",sum);

    }

    使用_bool 变量

    #include <stdio.h>

    void main()

    {

        long num ;

        long sum = 0l;

        _Bool input_is_good ;

        printf("plese enter an integer to be summed ");

        printf("(q to quit ):");

        input_is_good = (scanf("%ld", &num)==1);

        while (input_is_good) {

            sum += sum;

            printf("please enter next integer (q to quit ");

             input_is_good = (scanf("%ld", &num)==1);

        }

        printf("those integers sum to %ld ",sum);

    }

    一个计数程序

    #include <stdio.h>

    void main()

    {

        const int  NUMBER =22;

        int count = 1 ;

        while (count < NUMBER) {

            printf("Be my valentine %10d\n" , count );

            count ++;

        }

    }

    for 循环

    #include <stdio.h>

    void main()

    {

        const int  NUMBER =22;

        intcount  ;

        for (count = 1;  count < NUMBER; count ++) {

            printf("Be my valentine %10d  \n", count);

        }

    }

    for 自减

    #include <stdio.h>

    void main()

    {

        int secs;

        for (secs = 5 ; secs; secs --) {

            printf("%d seconds \n",secs);

        }

        printf("we have ignition \n");

    }

    用字符代替数字进行计数

    #include <stdio.h>

    void main()

    {

        int n ;

        char ch ;

        for(ch  ='a'; ch <= 'z'; ch ++) {

            printf("ch = %c  %d\n",ch,ch);

        }

        for (n = 2;  n <60 ; n += 12 ) {

            printf("n = %d \n", n);

        }

    }

    yong 

    #include <stdio.h>

    void main()

    {

        int x ;

        int y = 55;

        for (x = 1;  y <=75 ; y = (++x *5)  +50 ) {   

            printf("%10d %10d \n",x,y);

        }

    }

    可以让一个活着多个表达式为空,但不要遗漏 ,只须 确保在循环中包含了一些能使循环最终结束的语句

    #include <stdio.h>

    void main()

    {

        int ans , n ;

        ans  =2;

        for (n = 3 ; ans <=25 ; ) {

            ans *= n ;

        }

        printf("n =%5d ,ans = %d \n",n ,ans);

    }

    #include <stdio.h>

    void main()

    {

        int num = 0 ;

        for (printf(" keep entering num bers \n"); num != 6; ) {

            scanf("%d",&num);

        }

         printf("that's the one I wangt \n");

    }

    逗号运算符

    #include <stdio.h>

    void main()

    {

        const int FIRST_oz = 37;

        const int NEXT_oz = 23;

        intonuces ,cost    ;

        for (onuces = 1 ,cost = FIRST_oz;onuces <= 16; onuces++, cost += NEXT_oz    ) {

            printf("%5d $%4.2f \n",onuces,cost/100.0);

        }

    }

    序列数的和

    #include <stdio.h>

    void main()

    {

        int t_ct , limit;

        double time ,x;

        printf("enter the number of terms you want ;");

        scanf("%d",&limit);

        for (time = 0 , x = 1 ,t_ct = 1; t_ct <= limit; t_ct++,x *= 2.0) {

            time +=1.0/x;

            printf("time = %f whe terms = %d .\n ",time,t_ct);

        }

    }

    推出条件循环

    #include <stdio.h>

    void main()

    {

        const int secret_code = 13 ;

        int code_entered ;

        do

        {

            printf(" to enter the triskaidekaphobia therapy club ,\n");

            printf("please enter the secret code number ");

            scanf("%d",&code_entered);

        }

        while (code_entered != secret_code);

        printf(" congratulations ,your are cured ");

    }

    入口条件

    #include <stdio.h>

    void main()

    {

        const int secret_code = 13;

        int code_entered ;

        printf("to enter the triskaidekaphobia therapy club \n");

        printf("please enter the secret code number \n");

        scanf("%d",&code_entered);

        while (code_entered != secret_code) {

            printf("to enter the triskaidekaphobia therapy club \n");

            printf("please enter the secret code number \n");

            scanf("%d",&code_entered);

        }

        printf(" congratulation you are cured \n");

    }

    for循环嵌套

    #include <stdio.h>

    #define ROWS 6 

    #define CHAES 10

    void main()

    {

        int  row;

        char ch ;

        for (row = 0 ; row < ROWS; row++) {

            for (ch = 'A'; ch < ('A' + CHAES); ch++ ) {

                printf(" %c",ch);

            }

            printf("\n");

        }

    }

    f

    使内部循环依赖于外部循环的嵌套循环

    #include <stdio.h>

    #define ROWS 6 

    #define CHAES 6

    void main()

    {

        int  row;

        char ch ;

        for (row = 0 ; row < ROWS; row++) {

            for (ch = 'A'+row ; ch < ('A' + CHAES); ch++ ) {

                printf(" %c",ch);

            }

            printf("\n");

        }

    }

    使用循环进行数组处理

    #include <stdio.h>

    #define SIZE 10

    #define PAR 72

    void main()

    {

        int index ,score[SIZE];

        int sum = 0; float avage ;

        printf("enter %d golf scores \n ",SIZE);

        for (index = 0 ; index < SIZE ; index ++ ) {

            scanf("%d",&score[index]);

        }

        printf("the scores read in are sa follows \n");

        for (index = 0 ; index < SIZE; index++) {

            printf("%5d",score[index]);

        }

        printf("\n");

        for ( index = 0 ; index < SIZE ; index++) {

            sum += score[index];

        }

        avage = (float) sum / SIZE;

        printf("sum of score = %d average = %.2f\n",sum ,avage);

        printf("that's a handicap of %.0f .\n",avage-PAR);

    }

    s

    计算数值的整数次幂

    #include <stdio.h>

    double power (double n ,int p )

    {

        double pow = 1 ;

        int  i ;

        for (i = 1;  i <= p ; i ++) {

            pow *= n;

        }

        return pow;

    }

    void main()

    {

        double x ,xpow ;

        int exp ;

        printf("Enter a number and the positive intefger power ");

        printf("to which \n the number will be raised enter q");

        printf(" to quit \n");

        while (scanf( "%lf%d",&x,&exp) == 2)//成功的读取了两个数值,并返回2

        {

            xpow =power(x,exp);

            printf(" %.3g to the ower %d is %.5g \n ", x ,exp,xpow);

            printf("Enter next pair of numbers of q to tuit.\n");

        }

        printf("hope you enjoyed this power trip ---bye ! \n");

    }

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