Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.
For example:
Given the below binary tree and sum = 22,
5
/ \
4 8
/ / \
11 13 4
/ \ / \
7 2 5 1
return
[
[5,4,11,2],
[5,8,4,5]
]
class Solution {
public:
vector<vector<int>> pathSum(TreeNode* root, int sum) {
vector<vector<int>> result;
vector<int> a;
dfs(root,sum,a,result);
return result;
}
void dfs(TreeNode* root,int sum,vector<int> &a,vector<vector<int>> &result)
{
if(root == NULL)
return;
a.push_back(root->val);
if(root->left == NULL&&root->right == NULL)
if(sum-root->val == 0)
result.push_back(a);
dfs(root->left,sum-root->val,a,result);
dfs(root->right,sum-root->val,a,result);
a.pop_back();
}
};
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