vue获取url地址中的参数

首先获取到url地址

let geturl = window.location.href 
// http://localhost:8081/#/pages/index/index?qycode=1001&qyname=%E4%BC%81%E4%B8%9A%E5%BF%99

方式一

let getqyinfo = geturl.split('?')[1]   //qycode=1001&qyname=%E4%BC%81%E4%B8%9A%E5%BF%99   截取到参数部分
let getqys = new URLSearchParams('?'+getqyinfo)  //将参数放在URLSearchParams函数中
let getqycode = getqys.get('qycode')   //1001   
let getqyname = getqys.get('qyname')  //%E4%BC%81%E4%B8%9A%E5%BF%99

方式二

let getqyinfo = geturl.split('?')[1]   //qycode=1001&qyname=%E4%BC%81%E4%B8%9A%E5%BF%99
let getqys = getqyinfo.split('&')  //['qycode=1001', 'qyname=%E4%BC%81%E4%B8%9A%E5%BF%99%E5%95%8A%E5%95%8A%E5%95%8A']
let getqycode =  getqys[0].split('=')[1]
let getqyname = getqys[1].split('=')[1] 
console.log('qycode:',getqycode,'getqyname:',getqyname)

方式三

let getqyinfo = geturl.split('?')[1]
let getqys = getqyinfo.split('&')
let obj = {}  //创建空对象，接收截取的参数
for(let i = 0;i < getqys.length;i++ ){
    console.log(i)
    let item = getqys[i].split('=')
    let key = item[0]
    let value = item[1]
    obj[key] = value 
}
console.log(obj) 

作者：资深Bug开发大师
链接：https://www.jianshu.com/p/72289467a54b
来源：简书
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