lua 同时 截取中文和英文字符串处理

原文: http://blog.csdn.net/fenrir_sun/article/details/52232723

lua 用

string.sub("大", 1, 1)--结果乱码

所以有了以上这个需求

全局函数

function SubStringUTF8(str, startIndex, endIndex)
    if startIndex < 0 then
        startIndex = SubStringGetTotalIndex(str) + startIndex + 1;
    end

    if endIndex ~= nil and endIndex < 0 then
        endIndex = SubStringGetTotalIndex(str) + endIndex + 1;
    end

    if endIndex == nil then 
        return string.sub(str, SubStringGetTrueIndex(str, startIndex));
    else
        return string.sub(str, SubStringGetTrueIndex(str, startIndex), SubStringGetTrueIndex(str, endIndex + 1) - 1);
    end
end

--获取中英混合UTF8字符串的真实字符数量
function SubStringGetTotalIndex(str)
    local curIndex = 0;
    local i = 1;
    local lastCount = 1;
    repeat 
        lastCount = SubStringGetByteCount(str, i)
        i = i + lastCount;
        curIndex = curIndex + 1;
    until(lastCount == 0);
    return curIndex - 1;
end

function SubStringGetTrueIndex(str, index)
    local curIndex = 0;
    local i = 1;
    local lastCount = 1;
    repeat 
        lastCount = SubStringGetByteCount(str, i)
        i = i + lastCount;
        curIndex = curIndex + 1;
    until(curIndex >= index);
    return i - lastCount;
end

--返回当前字符实际占用的字符数
function SubStringGetByteCount(str, index)
    local curByte = string.byte(str, index)
    local byteCount = 1;
    if curByte == nil then
        byteCount = 0
    elseif curByte > 0 and curByte <= 127 then
        byteCount = 1
    elseif curByte>=192 and curByte<=223 then
        byteCount = 2
    elseif curByte>=224 and curByte<=239 then
        byteCount = 3
    elseif curByte>=240 and curByte<=247 then
        byteCount = 4
    end
    return byteCount;
end

具体使用

    local szHhName = "大风兄弟"
    local szHhName2 = "aaa"
    local szHhName2 = "AAA"
    local szHhOne = SubStringUTF8(szHhName2, 1, 1)--结果"大"
    self.m_Label_FlagName:setString(szHhOne)