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iOS view内进行push或present界面跳转

iOS view内进行push或present界面跳转

作者: liuzhongyi | 来源:发表于2018-05-24 17:59 被阅读508次

    最近梳理了一下如何在view内进行界面的跳转方法

    1.代理方法实现。不做多余的说明了。

    2.Block方法实现。同样不多说了。

    3.看代码

    4.采用AppDelegate实现(在需要实现跳转的view(testView.m)里写下如下代码)

    //1view present

        FirstViewController *jump = [[FirstViewController alloc]init];

        AppDelegate *app1 = (AppDelegate *)[UIApplication sharedApplication].delegate;

        [app1.window.rootViewController presentViewController:jump animated:YES completion:nil];

        //2view push

        FirstViewController *jump = [[FirstViewController alloc]init];

        AppDelegate *app2 = (AppDelegate *)[UIApplication sharedApplication].delegate;

        UINavigationController *navi = (UINavigationController *)app2.window.rootViewController;

        [navi pushViewController:jump animated:YES];

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