《父与子》练习7-1

7-1要检查一个数是否大于 30 但小于或 等于 40，要用哪种 if 语句

my_number = int(raw_input("Enter your number:"))
print my_number,type(my_number)
if (my_number > 30 and my_number <40) or my_number == 40:
    print '30 or <=40 '
else:
    print '41 or over'```
####7-4

aword = raw_input("enter a q or Q: ")
if aword == "Q" or aword =='q'
print"you got a 'q'."

**同学的答案7-1**

if (30 < my_number <= 40):
print (…)
else:
print (…)

if (my_number<=30 or my_number>40):
print'no'
else:
print'yes'```

动手试一试

7-1

你在超市购物，如果购买金额小于10，有10%的优惠，如果金额大于10，有20%的优惠，设计一个程序，询问你的购买金额，并做出判断优惠，然后显示折扣和购物总金额。

import easygui
buy_price =easygui.integerbox("How much you pay for shoppping?")
if buy_price <=10:
    easygui.msgbox("you got 10% salez")
    buy_price =float(buy_price*(1-0.1))
    easygui.msgbox("you cost " + str(buy_price))
elif buy_price >10:
    easygui.msgbox( "you got 20% salez")
    buy_price =float(buy_price*(1-0.2))
    easygui.msgbox("you cost " + str(buy_price))```

修改后

import easygui
buy_price =easygui.integerbox("How much you pay for Items ?")
price = float(buy_price)
if price <=10.0:
discount = price0.10
elif price >10.0:
discount = price0.20
final_price = price - discount
easygui.msgbox("you got "+str(discount)+'off,your final_price was'+str(final_price))

```easygui.msgbox()
输出str,要用+连接，保证输出内容格式为str,需要转换int，float 格式。
而print 输出，可以包含不同格式，用“，”连接。```

7-2
**编程，正组建一个女子足球队，询问对方的年龄和性别，（m， f 表示男性和女性），并且年纪在10至12岁之间，才能加入足球队，提示是，先询问性别，性别不符合，可以不询问年纪。然后输出相应的提示**

football = raw_input("Are you m or f? ")
if football =="m":
print "Sorry,you can't join us."
elif football =="f":
age = int(raw_input("how old are you? "))
if age >=10 or age<=12:
print "You are allowed to joined our footballteam!"
else:
print "Sorry,you can't join us."```
7-3
你在长途旅行，刚到一个加油站，距下一个加油站还有 200 km。编写一个程序确定是不是需要在这里加油，还是可以等到下一个加油站再加油。
这个程序应当问下面几个问题。
你的油箱有多大（单位是升）？
油箱有多满（按百分比，例如，半满就是 50%）？
你的汽车每升油可以走多远（km）？
输出应该像这样：

Size of tank:  60
percent full:  40
km per liter:  10
You can go another 240 km
The next gas station is 200 km away
You can wait for the next station.```
或

Size of tank: 60
percent full: 30
km per liter: 8
You can go another 144 km
The next gas station is 200 km away
Get gas now!

代码清单7-3

how_size = int(raw_input("how size of your oil-box? liter:"))

percent = int(raw_input("how percent full of a oil-box? %:"))
p = percent/100.0

how_long= int(raw_input("how long km per a liter oil ? km:"))
print"Size of tank:",how_size
print "percent full:",percent
print "km per liter:",how_long
along=int(how_sizephow_long)
if along > 205:
print "The next gas station is 200km away" ,
print"You can wait for the next station."
elif along < 205:
print "You can go another",str(along)+"km",
print"The next gas station is 200 km away.",
print"Get gas now!"```

动手7-4
建立一个程序，用户必须输入密码才能使用这个程序。你当然知道密码（因为它会写在你的代码中）。不过，你的朋友要得到这个密码就必须问你或者直接猜，也可以学习足够的 Python 知识查看代码来找出密码！

*代码是写出来了，但是问题无法重复调用，除非是把这个逻辑放到一个定义函数里，再调用函数才行,才能达到输入密码三次就会锁定账户的功能，不然只会执行一次。写这段代码，是因为之前看过别的python书，里面有个例子就是写账户登录输入密码，所以就把那个借鉴过来了

• -||*

#-*- coding utf-8 -*-
import easygui
password_list =['*#*#','123456']
##password=easygui.enterbox('Enter the password')
tries=3
if tries>0:
    password=easygui.enterbox('Enter the password')
    if password == password_list[-1]:
        easygui.msgbox( "You're in!")
    elif password == password_list[0]:
        new_password = easygui.enterbox("Enter a new password")
        password_list.append(new_password)
        easygui.msgbox("The password has changed sucessfully!")
    else:
        easygui.msgbox("Wrong password or invalid input")
        tries = tries-1
        easygui.msgbox(str(tries)+"time left")
else:
    easygui.msgbox("Your account has suspended!")