463. Island Perimeter

You are given a map in form of a two-dimensional integer grid where 1 represents land and 0 represents water. Grid cells are connected horizontally/vertically (not diagonally). The grid is completely surrounded by water, and there is exactly one island (i.e., one or more connected land cells). The island doesn't have "lakes" (water inside that isn't connected to the water around the island). One cell is a square with side length 1. The grid is rectangular, width and height don't exceed 100. Determine the perimeter of the island.

仍然是回溯法，需要改变的是要判断周围有几个已经访问过的

class Solution {
    public int islandPerimeter(int[][] grid) {
        int row = grid.length;
        int col = grid[0].length;
        boolean[][] visited = new boolean[row][col];
        int count = 0;
        for(int i = 0 ;i<row;i++)
        {
            for(int j = 0 ;j<col;j++)
            {
                if(!visited[i][j]&&grid[i][j]==1)
                {
                    count=search(grid,visited,i,j);
                }
            }
        }
        return count;
    }
    private int search(int[][] grid,boolean[][] visited,int i ,int j)
    {
         if(i<0||i>=grid.length)  return 0;
         if(j<0||j>=grid[0].length) return 0;
        if(grid[i][j]==0) return 0;
        if(visited[i][j])return 0;
        visited[i][j]=true;
        int per = 4;
        if(j<grid[0].length-1&&visited[i][j+1])
            per-=2;
        if (j>=1&&visited[i][j-1])
            per-=2;
       if (i>=1&&visited[i-1][j])
            per-=2;
       if (i<grid.length-1&&visited[i+1][j])
            per-=2;
        return per+search(grid,visited,i+1,j)+search(grid,visited,i-1,j)+
        search(grid,visited,i,j-1)+search(grid,visited,i,j+1);   
            
    }
}