三.排序查询
- 语法:select 查询列表字段 from 表 where 筛选条件 order by 排序列表的字段 asc|desc
- 特点:ASC:升序 DESC:降序。不写默认是升序。
- order by 子句中可以支持单个字段、多个字段、表达式、函数、别名
- order by 子句一般放到查询语句的最后面,limit子句除外(只有limit放在order by 后面)
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执行顺序
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案例一:查询员工信息:要求工资从高到底排序
SELECT * FROM employees ORDER BY salary DESC;
案例二:查询员工信息:要求工资从低到高排序,默认是从低到高的,所以不加asc也行
SELECT * FROM employees ORDER BY salary ASC;
SELECT * FROM employees ORDER BY salary;
案例三:查询部门编号>=90的员工信息,按入职时间的先后进行排序「添加筛选条件」
SELECT * FROM employees WHERE department_id>=90 ORDER BY hiredate ASC;
案例四:按年薪的高低显示员工的信息和年薪「按表达式排序」
SELECT *,salary*12*(1+IFNULL(commission_pct,0)) AS 年薪 FROM employees ORDER BY salary*12*(1+IFNULL(commission_pct,0)) DESC;
案例五:按年薪的高低显示员工的信息和年薪「按别名排序」
SELECT *,salary*12*(1+IFNULL(commission_pct,0)) AS 年薪 FROM employees ORDER BY 年薪 DESC;
案例六:按照姓名的长度显示员工的姓名和工资「按函数排序」
SELECT LENGTH(last_name) 字节长度,last_name,salary FROM employees ORDER BY LENGTH(last_name) DESC;
案例七:查询员工信息,要求先按工资排序,再按员工编号排序「按多个字段排序」 意思是:整体是salary从低到高,如果salary一样,那么按照employee_id从高到底
SELECT * FROM employees ORDER BY salary ASC,employee_id DESC;
练习
练习1.查询员工的名字和部门号和年薪,按年薪降序,按名字升序
SELECT last_name,department_id,salary*12*(1+IFNULL(commission_pct,0)) 年薪
FROM employees
ORDER BY 年薪 DESC,last_name ASC;
练习2.选择工资不在8000到17000的员工的姓名和工资,按工资降序。
SELECT last_name,salary
FROM employees
WHERE salary NOT BETWEEN 8000 AND 17000
-- WHERE salary<=8000||salary>=17000
ORDER BY salary DESC;
练习3. 查询邮箱中包含e的员工信息,并先按邮箱的字节数降序,再按部门号升序
SELECT *
FROM employees
WHERE email
LIKE '%e%'
ORDER BY LENGTH(email) DESC,department_id ASC;
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