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ios 侧滑返回

ios 侧滑返回

作者: Q6尐漒 | 来源:发表于2016-09-01 13:11 被阅读287次

ios7开始 苹果增加了页面 右滑返回的效果;具体的是以UINavigationController为容器的ViewController间右滑切换页面。代码里的设置是:self.navigationController.interactivePopGestureRecognizer.enabled = YES;(default is YES)

可以看到苹果给navigationController添加了一个手势(具体为UIScreenEdgePanGestureRecognizer(边缘手势,同样是ios7以后才有的)),就是利用这个手势实现的 ios7的侧滑返回。问题1:然而事情并非我们想的那么简单。

1.当我们用系统的UINavigationController,并且也是利用系统的navigateBar的时候,是完全没有问题的2.但是当我们没有用系统的navigateBar或者自定义了返回按钮的时候,这个时候 右滑返回是失效的。解决(问题1)办法:对于这种失效的情况,考虑到interactivePopGestureRecognizer也有delegate属性,替换默认的self.navigationController.interactivePopGestureRecognizer.delegate来配置右滑返回的表现也是可行的。我们可以在主NavigationController中设置一下:self.navigationController.interactivePopGestureRecognizer.delegate =(id)self问题2:但是出现很多问题,比如说在rootViewController的时候这个手势也可以响应,导致整个程序页面不响应;push了多层后,快速的触发两次手势,也会错乱解决(问题2)办法:

@interface NavRootViewController : UINavigationController

@property(nonatomic,weak) UIViewController* currentShowVC;

@end

@implementation NavRootViewController-(id)initWithRootViewController:(UIViewController *)rootViewController{

NavRootViewController* nvc = [super initWithRootViewController:rootViewController];

self.interactivePopGestureRecognizer.delegate = self;

nvc.delegate = self;return mvc;

-(void)navigationController:(UINavigationController *)navigationController willShowViewController:(UIViewController *)viewController animated:(BOOL)animated{

}

-(void)navigationController:(UINavigationController *)navigationController didShowViewController:(UIViewController *)viewController animated:(BOOL)animated{

if (navigationController.viewControllers.count == 1)self.currentShowVC = Nil;elseself.currentShowVC = viewController;

-(BOOL)gestureRecognizerShouldBegin:(UIGestureRecognizer *)gestureRecognizer{

if (gestureRecognizer == self.interactivePopGestureRecognizer) {return (self.currentShowVC == self.topViewController); //the most important}return YES;

@end

借鉴了别人的方法:具体是通过 获取当前pushView栈里的当前显示的VC,根据这个VC来决定 是否开启手势(如果currentShowVC 是当前显示的,则开启手势;如果 currentShowVC为nil,则代表在主页面,关闭手势)注:当时试了一种方法 就是滑动的时候来回设置 interactivePopGestureRecognizer的delegate;发现 会有crash,原因就是 因为 我把 当前显示的VC设置为了这个手势的delegate,但当这个VC消失的时候,这个delegate便被释放了,导致crash至此,觉得ios7上的右滑返回大功告成了,心里正happy,妈蛋,发现了一个可耻的bug:UIScrollView 上 右滑返回的手势失灵了,靠!!!!!!

问题三:UIScrollView上手势失灵:经研究,发现是UIScrollView上已经添加了 panGestureRecognizer(滑动)手势ios7侧滑返回解决(问题三)办法:参考:http://www.cnblogs.com/lexingyu/p/3702742.html【

解决方案】苹果以UIGestureRecognizerDelegate的形式,支持多个UIGestureRecognizer共存。其中的一个方法是:1 // called when the recognition of one of gestureRecognizer or otherGestureRecognizer would be blocked by the other 2 // return YES to allow both to recognize simultaneously. the default implementation returns NO (by default no two gestures can be recognized simultaneously) 3 // 4 // note: returning YES is guaranteed to allow simultaneous recognition. returning NO is not guaranteed to prevent simultaneous recognition, as the other gesture's delegate may return YES 5 - (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRecognizeSimultaneouslyWithGestureRecognizer:(UIGestureRecognizer *)otherGestureRecognizer; 一句话总结就是此方法返回YES时,手势事件会一直往下传递,不论当前层次是否对该事件进行响应。 

@implementation UIScrollView (AllowPanGestureEventPass)- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRecognizeSimultaneouslyWithGestureRecognizer:(UIGestureRecognizer *)otherGestureRecognizer{    

if ([gestureRecognizer isKindOfClass:[UIPanGestureRecognizer class]]        && [otherGestureRecognizer isKindOfClass:[UIScreenEdgePanGestureRecognizer class]])    {

        return YES;   

 }    else    { 

       return  NO;   

 }

}

事实上,对UIGestureRecognizer来说,它们对事件的接收顺序和对事件的响应是可以分开设置的,即存在接收链和响应链。接收链如上文所述,和UIView绑定,由UIView的层次决定接收顺序。而响应链在apple君的定义下,逻辑出奇的简单,只有一个方法可以设置多个gestureRecognizer的响应关系:// create a relationship with another gesture recognizer that will prevent this gesture's actions from being called until otherGestureRecognizer transitions to UIGestureRecognizerStateFailed // if otherGestureRecognizer transitions to UIGestureRecognizerStateRecognized or UIGestureRecognizerStateBegan then this recognizer will instead transition to UIGestureRecognizerStateFailed // example usage: a single tap may require a double tap to fail - (void)requireGestureRecognizerToFail:(UIGestureRecognizer *)otherGestureRecognizer;每个UIGesturerecognizer都是一个有限状态机,上述方法会在两个gestureRecognizer间建立一个依托于state的依赖关系,当被依赖的gestureRecognizer.state = failed时,另一个gestureRecognizer才能对手势进行响应。所以,只需要[_scrollView.panGestureRecognizer requireGestureRecognizerToFail:screenEdgePanGestureRecognizer];

 - (UIScreenEdgePanGestureRecognizer *)screenEdgePanGestureRecognizer{    UIScreenEdgePanGestureRecognizer *screenEdgePanGestureRecognizer = nil;    if (self.view.gestureRecognizers.count > 0)    { 

       for (UIGestureRecognizer *recognizer in self.view.gestureRecognizers)        { 

           if ([recognizer isKindOfClass:[UIScreenEdgePanGestureRecognizer class]])            { 

               screenEdgePanGestureRecognizer = (UIScreenEdgePanGestureRecognizer *)recognizer;                

break;            }        }    }    

return screenEdgePanGestureRecognizer;

}

参考:牛逼 解决了iOS7下滑动返回与ScrollView共存http://www.cnblogs.com/lexingyu/p/3702742.html更牛逼  解决了interactivePopGestureRecognizer.delegate 的 释放导致crash的问题http://www.2cto.com/kf/201401/272886.html

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