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servlet中的IllegalStateException

servlet中的IllegalStateException

作者: smileNicky | 来源:发表于2019-07-27 00:10 被阅读5次

    IllegalStateException在java web开发中比较常见,IllegalStateException的根本原因是java servlet在提交响应后,还尝试写内容

    所以避免IllegalStateException的一个好方法就是提交响应,比如forward或者redirect之后,就不要再写内容,一个方法是在redirect之后加上return;

    比如这个比较常见的IllegalStateException,原因就是已经sendRedirect,提交响应了,然后还尝试写内容,这样就导致了IllegalStateException

    Java.lang.IllegalStateException: Cannot call sendRedirect() after the response has been committed
    

    下面给出会异常的代码:

    public class LoginFilter extends OncePerRequestFilter{
       ...
        @Override
        protected void doFilterInternal(final HttpServletRequest request, HttpServletResponse response, FilterChain filterChain)
                throws ServletException, IOException {
            HttpServletRequest wrappedRequest = new RemoteUserRequestWrapper(request);
            if (StringUtils.isEmpty(wrappedRequest.getRemoteUser()) ) {
                response.sendRedirect("login.do");
                //return;
            }
            filterChain.doFilter(new RemoteUserRequestWrapper(request), response);
        }
    }
    

    这段代码response.sendRedirect之后,跳到 login.do,login.do里的代码逻辑是有再次重定向等等逻辑的,然后Filter里代码,没return,执行后是会IllegalStateException的

    然后只要在sendRedirect之后加上return就可以:

    public class LoginFilter extends OncePerRequestFilter{
       ...
        @Override
        protected void doFilterInternal(final HttpServletRequest request, HttpServletResponse response, FilterChain filterChain)
                throws ServletException, IOException {
            HttpServletRequest wrappedRequest = new RemoteUserRequestWrapper(request);
            if (StringUtils.isEmpty(wrappedRequest.getRemoteUser()) ) {
                response.sendRedirect("login.do");
                return;
            }
            filterChain.doFilter(new RemoteUserRequestWrapper(request), response);
        }
    }
    

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