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258. Add Digits(E)

258. Add Digits(E)

作者: BeijingIamback | 来源:发表于2016-03-21 18:08 被阅读11次

Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.

For example:

Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it.

代码1:

参考代码1

代码2:

数字的根

参考代码2

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