Valid Sudoku
作者:
敲一手烂代码 | 来源:发表于
2018-01-29 10:51 被阅读6次The Sudoku board could be partially filled, where empty cells are filled with the character '.'.
A partially filled sudoku which is valid.
Note:
A valid Sudoku board (partially filled) is not necessarily solvable. Only the filled cells need to be validated.
class Solution {
func isValidSudoku(_ board: [[Character]]) -> Bool {
for i in 0 ... 8 {
var rowSet = Set<Character>()
var colSet = Set<Character>()
var subBoxSet = Set<Character>()
let rowStart = (i / 3) * 3;
let colStart = (i % 3) * 3;
for j in 0 ... 8 {
if board[i][j] != "." {
if rowSet.contains(board[i][j]) {
return false
} else {
rowSet.insert(board[i][j])
}
}
if board[j][i] != "." {
if colSet.contains(board[j][i]) {
return false
} else {
colSet.insert(board[j][i])
}
}
if board[rowStart + j / 3][colStart + j % 3] != "." {
if subBoxSet.contains(board[rowStart + j / 3][colStart + j % 3]) {
return false
} else {
subBoxSet.insert(board[rowStart + j / 3][colStart + j % 3])
}
}
}
}
return true
}
}
本文标题:Valid Sudoku
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