day6-函数作业

1. 编写一个函数，求1+2+3+...+N

def  sum1(N):
    sum = 0
    for x in range(1,N+1):
        sum+=x
    print(sum)
sum1(10)

2. 编写一个函数，求多个数中的最大值

def  max_num(*arg):
    return max(arg)
max_num(12,33,24,45)

3. 编写一个函数，实现摇骰子的功能，打印n个骰子的点数和

import random
def my_sum(n):
    count = 0
    for _ in range(n):
        point = random.randint(1, 6)
        count += point
        return count
print(my_sum(5))

4. 编写一个函数，交换指定字典的key和value。
   如:{'a':1, 'b':2, 'c':3} ---> {1:'a', 2:'b', 3:'c'}

dict1 = {'a':1, 'b':2, 'c':3}
def  exchange(dict1:dict):
    new_dict = {}
    for i  in  dict1:
        new_dict[dict1[i]] = i
    return new_dict
print(exchange(dict1))

5. 编写一个函数，提取指定字符串中的所有的字母，然后拼接在一起后打印出来
   如:'12a&bc12d--' ---> 打印'abcd'

def  zimu(str1:str):
    new_str = ""
    for  i in range(len(str1)):
        if "a" <= str1[i]<= "z" or "A" <= str1[i] <= "Z":
            new_str+=str1[i]
    print(new_str)
zimu("12a&bc12d--")

6. 写一个函数，求多个数的平均值

def  mean(*n):
    sum1 = sum(n)
    means = sum1/len(n)
    return means
    print("平均数是:%.2f" %  means)

print(mean(1,2,4,10,29))

7. 写一个函数，默认求10的阶层，也可以求其他数的阶层

def  product(n):
    sum = 1
    for  x in range(1,n+1):
        sum *= x
    return sum
re=product(10)
print(re)

8. 写一个函数，可以对多个数进行不同的运算
   如: operation('+', 1, 2, 3) ---> 求 1+2+3的结果 operation('-', 10, 9) ---> 求 10-9的结果 operation('', 2, 4, 8, 10) ---> 求 24810的结构

def calculate(oper, *nums):
    sum1 = nums[0]
    if oper == '+':
        for num in nums[1:]:
            sum1 += num
    elif oper == '-':
        for num in nums[1:]:
            sum1 -= num
    elif oper == '*':
        for num in nums[1:]:
            sum1 *= num
    elif oper == '/':
        for num in nums[1:]:
            sum1 /= num


    return sum1

num = calculate('+', 1, 2, 3)
print(num)  # 6
num2 = calculate('-', 10, 9)
print(num2)  # 1
num3 = calculate('*', 2, 4, 8, 10)
print(num3)

9.写一个函数，求指定列表中，指定的元素的个数

def count_num(any_list,any_item):
    sum1 = 0
    for item in any_list:
        if item == any_item:
            sum1 += 1

    return sum1


list1 = [1, 3, 1, 4, 5, 2, 0]
num = count_num(list1, 1)
print(num)  # 2

10.写一个函数，获取指定列表中指定元素对应的下标(如果有多个，一起返回)

def get_index(any_list, any_item):
    index_list = []
    index = 0
    while index < len(any_list):
        if any_list[index] == any_item:
            index_list.append(index)
        index += 1

    return index_list


list1 = [1, 3, 1, 4, 5, 2, 0]
index_list1 = get_index(list1,1)
print(index_list1)  # [0, 2]