题意
给定两个以字符串形式表示的非负整数 num1 和 num2,返回 num1 和 num2 的乘积,它们的乘积也表示为字符串形式
示例1:
输入: num1 = "2", num2 = "3"
输出: "6"
示例2:
输入: num1 = "123", num2 = "456"
输出: "56088"
示例3:
输入: num1 = "999999999", num2 = "999999999"
输出: "999999998000000001"
解题思路:
模拟乘法公式进行计算
1 2 3
* 2 2
-------------------------
2 4 6
2 4 6
-------------------------
2 7 0 6
代码
class Solution
{
/**
* @param String $num1
* @param String $num2
* @return String
*/
public function multiply($num1, $num2)
{
if ($num1 == '0' || $num2 == '0') {
return '0';
}
$strNum1 = $num1;
$strNum2 = $num2;
if (strlen($num1) < strlen($num2)) {
$strNum1 = $num2;
$strNum2 = $num1;
}
$size1 = strlen($strNum1) - 1;
$size2 = strlen($strNum2) - 1;
$sumArr = [];
$k = 0;
//乘法公式计算
for ($i = $size2; $i >= 0; $i--) {
$q = 0;
$sum = ($k++ > 0) ? array_pad([], $k - 1, 0) : [];
for ($j = $size1; $j >= 0; $j--) {
$num = $strNum2{$i} * $strNum1{$j} +$q;
$c = $num % 10;
$q = ($c != $num) ? floor($num / 10) : 0;
$sum[] = $c;
}
if ($q != 0) {
$sum[] = $q;
}
$sumArr[] = $sum;
}
//加法公式计算
$i = 0;
$q = 0;
$end = count($sum);
$sum = [];
while (1) {
$num = 0;
foreach ($sumArr as $item) {
$num += $item[$i];
}
$num = (($q != 0) ? $num + $q : $num);
if ($i >= $end) {
($q != 0) ? $sum[] = $q : null;
break;
}
$c = $num % 10;
$q = ($c != $num) ? floor($num / 10) : 0;
$sum[] = $c;
$i++;
}
return join(array_reverse($sum), '');
}
}
测试
print_r((new Solution())->multiply('123', '22')); //输出:2706
print_r((new Solution())->multiply('2', '3')); //输出:6
print_r((new Solution())->multiply('123', '456')); //输出:56088
print_r((new Solution())->multiply('999999999', '999999999')); //输出:999999998000000001
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