JsonObject 使用注意

• import com.google.gson.JsonObject
• import org.json.JSONObject
• 方法

    public void sendEmailUseXUrl( EmailXSendParams emailXSendParams){
        JSONObject jsonObject=new JSONObject();
        jsonObject.put("appid","");
        jsonObject.put("name",emailXSendParams.getAppId());
        System.out.println(jsonObject.toString());

        JsonObject jsonObject1=new JsonObject();
        jsonObject1.addProperty("appId","");
        jsonObject1.addProperty("name",emailXSendParams.getAppId());
        System.out.println(jsonObject1.toString());
    }

• 调用

    public void sendEmailUseXUrl() {
        EmailXSendParams emailXSendParams=new EmailXSendParams();
        emailService.sendEmailUseXUrl(emailXSendParams);
    }

• 结果

{"appid":""}
{"appId":"","name":null}

• 观察：当对象中的参数为null时，gson会正常生成Json格式，而json会将其忽略
• 结论：因势利导，善用之！