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279. Perfect Squares

279. Perfect Squares

作者: HalcyonMoon | 来源:发表于2016-06-29 23:16 被阅读0次

    Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n.

    For example,

    given *n* = 12, return 3 because 12 = 4 + 4 + 4; 
    given *n* = 13,    return 2 because 13 = 4 + 9.
    
    public class Solution {
        public int numSquares(int n) {
            int dp[] = new int[n+1];
            dp[0] = 0;
            for(int i = 1; i<=n; i++){
                dp[i] = Integer.MAX_VALUE;
                for(int j = 1; j*j<=i ;j++ ){
                    if(dp[i] > dp[i - j*j] + 1){
                        dp[i] = dp[i-j*j] + 1;
                    }
                }
            }
            return dp[n];
        }
    }
    

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