169. Majority Element

作者: 番茄晓蛋 | 来源:发表于2017-06-12 15:47 被阅读7次

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    Total Accepted: 192332
    Total Submissions: 417285
    Difficulty: Easy
    Contributor: LeetCode

    Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋
    times.
    You may assume that the array is non-empty and the majority element always exist in the array.
    Credits:Special thanks to @ts for adding this problem and creating all test cases.

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    Array Divide and Conquer Bit Manipulation
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    (M) Majority Element II

    public class Solution {
        // O(n) time O(1) space fastest solution
        public int majorityElement(int[] nums) {
            int major = nums[0], count = 1;
            for (int i = 1; i < nums.length; i++) {
                if (count == 0) {
                    count++;
                    major = nums[i];
                } else if (major == nums[i]) {
                    count++;
                } else {
                    count--;
                }
            }
            return major;
        }
        
        public int majorityElementFailed(int[] nums) {
            Set<Integer> set = new HashSet<>();
            for (int n : nums) {
                set.add(n);
            }
            int max = -1;
            
            int[] countList = new int[nums.length];
            
            for (int k : set) {
               for (int i = 0; i < nums.length; i++) {
                   if (nums[i] == k) countList[i]++;
               }
            }
            return max;
        }
    }
    

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