题目要求:
Given a string s and a string t, check if s is subsequence of t.
You may assume that there is only lower case English letters in both s and t. t is potentially a very long (length ~= 500,000) string, and s is a short string (<=100).
A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ace" is a subsequence of "abcde" while "aec" is not).
Examples:
s = "abc", t = "ahbgdc"
Return true.
Example 2:
s = "axc", t = "ahbgdc"
Return false.
解题思路:
- 看了代码就很容易明白了
class Solution(object):
def isSubsequence(self, s, t):
"""
:param s:
:param t:
:return:
"""
if not s:
return True
num = 0
for i in range(len(t)):
if s[num] == t[i]:
num += 1
if num == len(s):
break
return num == len(s)
if __name__ == "__main__":
print(Solution.isSubsequence(self=None, s = "axc", t = "ahbxc"))
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