iOS限制输入表情(emoji)，出现九宫格不能输入的解决方法

1.九宫格读取出来是 ➋➌➍➎➏➐➑➒
处理方法是判断是否为九宫格
2.关于一些第三方输入表情的问题
3.♥️ 这个还是识别不出来，如果哪位朋友能识别出来请留言告知 万分感谢

• (BOOL)stringContainsEmoji:(NSString *)string
  {
  if ([self isNineKeyBoard:string]) {
  return NO;
  }

  if ([self hasEmoji:string]) {
  return YES;
  }

  __block BOOL returnValue = NO;

  [string enumerateSubstringsInRange:NSMakeRange(0, [string length])
  options:NSStringEnumerationByComposedCharacterSequences
  usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
  const unichar hs = [substring characterAtIndex:0];
  if (0xd800 <= hs && hs <= 0xdbff) {
  if (substring.length > 1) {
  const unichar ls = [substring characterAtIndex:1];
  const int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;
  if (0x1d000 <= uc && uc <= 0x1f77f) {
  returnValue = YES;
  }
  }
  } else if (substring.length > 1) {
  const unichar ls = [substring characterAtIndex:1];
  if (ls == 0x20e3) {
  returnValue = YES;
  }
  } else {
  if (0x2100 <= hs && hs <= 0x27ff) {
  returnValue = YES;
  } else if (0x2B05 <= hs && hs <= 0x2b07) {
  returnValue = YES;
  } else if (0x2934 <= hs && hs <= 0x2935) {
  returnValue = YES;
  } else if (0x3297 <= hs && hs <= 0x3299) {
  returnValue = YES;
  } else if (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030 || hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b || hs == 0x2b50) {
  returnValue = YES;
  }
  }
  }];

  return returnValue;
  }

/**
判断是不是九宫格
@param string 输入的字符
@return YES(是九宫格拼音键盘)
*/

• (BOOL)isNineKeyBoard:(NSString *)string
  {
  NSString *other = @"➋➌➍➎➏➐➑➒";
  int len = (int)string.length;
  for(int i=0;i<len;i++)
  {
  if(!([other rangeOfString:string].location != NSNotFound))
  return NO;
  }
  return YES;
  }

/**

• 判断字符串中是否存在emoji
• 利用下面这个方法hasEmoji可以限制第三方键盘（常用的是搜狗键盘）的表情
• @param string 字符串
• @return YES(含有表情)
  */

• (BOOL)hasEmoji:(NSString*)string
  {
  NSString *pattern = @"[^\u0020-\u007E\u00A0-\u00BE\u2E80-\uA4CF\uF900-\uFAFF\uFE30-\uFE4F\uFF00-\uFFEF\u0080-\u009F\u2000-\u201f\r\n]";
  NSPredicate *pred = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", pattern];
  BOOL isMatch = [pred evaluateWithObject:string];
  return isMatch;
  }

https://www.jianshu.com/p/d0f6c62b57e1