scala 接收函数作为参数及返回函数

scala 接收函数作为参数及返回函数

object FunctionDemo {
  
  /**
   * 定义函数
   * 参数类型为函数
   * 返回类型为函数
   */
  def func(name1: String, name2: String, f: (Int, Int) => String): (String, Int) => Int = {
    val temp = f(1, 2)
    (a: String, b: Int) => {
      a.size + b + temp.size
    }
  }

  val value = func("name1", "name2", (a: Int, b: Int) => {
    (a + b).toString()
  })("aaa", 10)

  println(value)
  
  def main(args: Array[String]): Unit = {
    
  }
}