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Total Accepted: 221656
Total Submissions: 571422
Difficulty: Easy
Contributor: LeetCode
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
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(H) Merge k Sorted Lists (E) Merge Sorted Array (M) Sort List (M) Shortest Word Distance II
** 解题思路**
recursive 递归解法。 类似merge two sorted array
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
public class Solution {
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
// use recursive
if (l2 == null) return l1;
if (l1 == null) return l2;
ListNode mergeHead;
if (l1.val < l2.val) {
mergeHead = l1;
mergeHead.next = mergeTwoLists(l1.next, l2);
} else {
mergeHead = l2;
mergeHead.next = mergeTwoLists(l1, l2.next);
}
return mergeHead;
}
public ListNode mergeTwoListsFailed(ListNode l1, ListNode l2) {
ListNode p1 = l1;
ListNode p2 = l2 ;
ListNode p = new ListNode(0);
while (p1 != null && p2 != null) {
// p.next = (p1.val > p2.val) ? new ListNode(p1.val) : new ListNode(p2.val);
if (p1.val > p2.val) {
p.next = new ListNode(p1.val);
p1 = p1.next;
} else {
p.next = new ListNode(p2.val);
p2 = p2.next;
}
}
while (p2 != null) {
p.next = new ListNode(p2.val);
p2 = p2.next;
}
while (p1 != null) {
p.next = new ListNode(p1.val);
p1 = p1.next;
}
return p;
}
}
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