674. Longest Continuous Increasi

Problem

Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray).

Example 1:

Input: [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. 
Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4. 

Example 2:

Input: [2,2,2,2,2]
Output: 1
Explanation: The longest continuous increasing subsequence is [2], its length is 1. 

Note: Length of the array will not exceed 10,000.

Solution

class Solution {
public:
    int findLengthOfLCIS(vector<int>& nums) {
        int len = nums.size();
        int longest = INT_MIN;
        if(len==0)return 0;
        int pre=nums[0];
        int count=1;
        for(int i=1;i<len;i++){
            if(nums[i]>pre){
                count++;
                pre=nums[i];
            }else{
                longest=max(longest,count);
                pre=nums[i];
                count=1;
            }
        }
        longest=max(longest,count);
        return longest;
    }
};
static auto speedup = [](){
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    return nullptr;
}();

image-20190228092013276-1316813.png