美文网首页
【leetcode 36】 Valid Sudoku 判断数独是

【leetcode 36】 Valid Sudoku 判断数独是

作者: 齐鑫 | 来源:发表于2020-01-31 17:15 被阅读0次

    题目

    Determine if a 9x9 Sudoku board is valid. Only the filled cells need to be validated according to the following rules:

    Each row must contain the digits 1-9 without repetition.
    Each column must contain the digits 1-9 without repetition.
    Each of the 9 3x3 sub-boxes of the grid must contain the digits 1-9 without repetition.

    A partially filled sudoku which is valid.

    The Sudoku board could be partially filled, where empty cells are filled with the character '.'.

    Example 1:

    Input:
    [
    ["5","3",".",".","7",".",".",".","."],
    ["6",".",".","1","9","5",".",".","."],
    [".","9","8",".",".",".",".","6","."],
    ["8",".",".",".","6",".",".",".","3"],
    ["4",".",".","8",".","3",".",".","1"],
    ["7",".",".",".","2",".",".",".","6"],
    [".","6",".",".",".",".","2","8","."],
    [".",".",".","4","1","9",".",".","5"],
    [".",".",".",".","8",".",".","7","9"]
    ]
    Output: true
    Example 2:

    Input:
    [
    ["8","3",".",".","7",".",".",".","."],
    ["6",".",".","1","9","5",".",".","."],
    [".","9","8",".",".",".",".","6","."],
    ["8",".",".",".","6",".",".",".","3"],
    ["4",".",".","8",".","3",".",".","1"],
    ["7",".",".",".","2",".",".",".","6"],
    [".","6",".",".",".",".","2","8","."],
    [".",".",".","4","1","9",".",".","5"],
    [".",".",".",".","8",".",".","7","9"]
    ]
    Output: false
    Explanation: Same as Example 1, except with the 5 in the top left corner being
    modified to 8. Since there are two 8's in the top left 3x3 sub-box, it is invalid.
    Note:

    • A Sudoku board (partially filled) could be valid but is not necessarily solvable.
    • Only the filled cells need to be validated according to the mentioned rules.
    • The given board contain only digits 1-9 and the character '.'.
    • The given board size is always 9x9.

    解题思路

    玩过数独的人都应该清楚,本题就是要求对给出的9*9数组进行验证,如果满足:

    1、横向数字只有1-9且不重复("."为补充占位,后续不再解释)

    2、竖向数字只有1-9且不重复

    3、把99的矩阵分成9个33的矩阵,每个矩阵中数字只有1-9且不重复

    依照上面的解题思路,就是要对9*9的矩阵进行3次判断,全部校验通过则通过,反之不通过。

    代码实现

    以下为具体代码实现,仅供参考

    public class Main {
     
     
        public static void main(String[] args) {
            Main main = new Main();
            char[][] arr = main.init();
            main.isValidSudoku(arr);
     
        }
     
        // 包含元素集合
        private Character[] demo = {'1', '2', '3', '4', '5', '6', '7', '8', '9', '.'};
     
        public boolean isValidSudoku(char[][] board) {
            if (checkHorizontal(board) && checkVertical(board) && checkGrid(board)) {
                System.out.println(true);
                return true;
            } else {
                System.out.println(false);
                return false;
            }
     
        }
     
        /**
         * 初始化数组
         *
         * @return
         */
        private char[][] init() {
            char[][] arr = {
                    {'5', '3', '.', '.', '7', '.', '.', '.', '.'},
                    {'6', '.', '.', '1', '9', '5', '.', '.', '.'},
                    {'.', '9', '8', '.', '.', '.', '.', '6', '.'},
                    {'8', '.', '.', '.', '6', '.', '.', '.', '3'},
                    {'4', '.', '.', '8', '.', '3', '.', '.', '1'},
                    {'7', '.', '.', '.', '2', '.', '.', '.', '6'},
                    {'.', '6', '.', '.', '.', '.', '2', '8', '.'},
                    {'.', '.', '.', '4', '1', '9', '.', '.', '5'},
                    {'.', '.', '.', '.', '8', '.', '.', '7', '9'}
            };
     
    //        char[][] arr = {{'8', '3', '.', '.', '7', '.', '.', '.', '.'},
    //                {'6', '.', '.', '1', '9', '5', '.', '.', '.'},
    //                {'.', '9', '8', '.', '.', '.', '.', '6', '.'},
    //                {'8', '.', '.', '.', '6', '.', '.', '.', '3'},
    //                {'4', '.', '.', '8', '.', '3', '.', '.', '1'},
    //                {'7', '.', '.', '.', '2', '.', '.', '.', '6'},
    //                {'.', '6', '.', '.', '.', '.', '2', '8', '.'},
    //                {'.', '.', '.', '4', '1', '9', '.', '.', '5'},
    //                {'.', '.', '.', '.', '8', '.', '.', '7', '9'}};
            return arr;
        }
     
        /**
         * 判断横向9个数字是否有重复
         *
         * @param arr
         * @return
         */
        private boolean checkHorizontal(char[][] arr) {
            List<Character> strings = Arrays.asList(demo);
            Set<Character> set = new HashSet<>();
            for (char[] a : arr) {
                set.clear();
                for (char aa : a) {
                    if (aa == '.') {
                        continue;
                    } else if (strings.contains(aa) && !set.contains(aa)) {
                        set.add(aa);
                    } else {
                        return false;
                    }
                }
            }
            return true;
        }
     
        /**
         * 判断竖向9个数字是否有重复
         *
         * @param arr
         * @return
         */
        private boolean checkVertical(char[][] arr) {
            char[][] tem = new char[9][9];
            // 将原9*9矩阵翻转
            for (int i = 0; i < 9; i++) {
                for (int j = 0; j < 9; j++) {
                    tem[j][i] = arr[i][j];
                }
            }
            return checkHorizontal(tem);
        }
     
        /**
         * 判断3*3的9个数字是否有重复
         *
         * @param arr
         * @return
         */
        private boolean checkGrid(char[][] arr) {
            char[][] tem = new char[9][9];
            for (int i = 0; i < 9; i++) {
                for (int j = 0; j < 9; j++) {
                    // [i / 3 * 3 + j / 3]:确认当前元素属于3*3矩阵中第几块
                    // [j % 3 * 3 + i % 3]:确认当前元素在所属元素块中是第几个元素
                    tem[i / 3 * 3 + j / 3][j % 3 * 3 + i % 3] = arr[i][j];
                }
            }
            return checkHorizontal(tem);
        }
     
    }
    

    相关文章

      网友评论

          本文标题:【leetcode 36】 Valid Sudoku 判断数独是

          本文链接:https://www.haomeiwen.com/subject/mrngthtx.html