原题链接：Contains Duplicate
本题用Python做非常简单。可以利用Python中set这种不包含重复元素的数据结构。
以下是我的解法：
class Solution:
# @param {integer[]} nums
# @return {boolean}
def containsDuplicate(self, nums):
seen = set()
for item in nums:
seen.add(item)
if len(seen) == len(nums):
return False
return TrueD90 217. Contains Duplicate 题目链接 217. Contains Duplicate ...
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原题链接：Contains Duplicate本题用Python做非常简单。可以利用Python中set这种不包含...
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本文标题：217 Contains Duplicate
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