For example, 128 is a self-dividing number because 128 % 1 == 0, 128 % 2 == 0, and 128 % 8 == 0.
Also, a self-dividing number is not allowed to contain the digit zero.
Given a lower and upper number bound, output a list of every possible self dividing number, including the bounds if possible.
Example 1:
Input:
left = 1, right = 22
Output: [1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15, 22]
Note:
The boundaries of each input argument are 1 <= left <= right <= 10000.
毕竟基本的题,主要想的是从个位开始往前一个个看能否满足要求,另外注意0的处理。
def selfDividingNumbers(self, left, right):
"""
:type left: int
:type right: int
:rtype: List[int]
"""
res = []
for i in range(left,right+1):
num = i
flag = 1
while i:
remain = i % 10
if not remain or num % remain != 0:
flag = 0
break
i /=10
if flag:
res.append(num)
return res```
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