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抱怨不如多练习

抱怨不如多练习

作者: 逻辑演绎法 | 来源:发表于2017-07-17 18:13 被阅读0次

    create database day16;

    use day16;
    //部门表
    create table dept(
    did int primary key auto_increment,
    dname varchar(30)
    );
    //职员表
    create table emp(
    eid int primary key auto_increment,
    ename varchar(20),
    salaly double,
    dno int
    );

    //查看所有编码

    show variables like 'char%';

    insert into dept values(null,'研发部');
    insert into dept values(null,'销售部');
    insert into dept values(null,'人事部');

    insert into emp(ename,salaly,dno) values('班长',10000,1);
    insert into emp(ename,salaly,dno) values('美美',40000,1);
    insert into emp(ename,salaly,dno) values('小凤',50000,1);

    update emp set dno = 2 where ename='美美';

    update emp set dno = 3 where ename='小凤';

    mysql> select * from dept;
    +-----+--------+
    | did | dname |
    +-----+--------+
    | 1 | 研发部 |
    | 2 | 销售部 |
    +-----+--------+
    2 rows in set (0.00 sec)

    mysql> select * from emp;
    +-----+-------+--------+------+
    | eid | ename | salaly | dno |
    +-----+-------+--------+------+
    | 1 | 班长 | 10000 | 1 |
    | 2 | 美美 | 40000 | 2 |
    | 3 | 小凤 | 50000 | 3 |
    +-----+-------+--------+------+
    3 rows in set (0.00 sec)

    像这种情况明显不合理 第一张表是部门表 而第二张员工表 员工表中小凤的这条数据dno对应的部门被

    删掉明显不合理,随便删掉明显不合理

    这中时候就需要多表设置外键来约束不能随便的删除一表的数据
    多表设计——外键约束
    作用:保证数据的完整性。
    定义外键约束

    可以直接在create语句中定义外键
    foreign key 当前表名 (字段名) references 目标表名 (目标表的主

    键)

    create table emp(
    eid int primary key auto_increment,
    ename varchar(20),
    salaly double,
    dno int,
    foreign key emp('dno') references dept('did');
    );

    create table renyuan
    (
    id int primary key ,
    name varchar(20) ,
    age int NOT NULL,
    sex varchar(2) ,
    address varchar(20) default '重庆'
    ) ;

    insert into renyuan (id,name,age,sex) values(1,'小李',12,'男');
    insert into renyuan (id,name,age,sex) values(2,'老王',32,'男');

    修改人员表的默认 address默认约束字段为null;

    ALTER TABLE renyuan CHANGE ename ename VARCHAR(20) NULL;

    alter table renyuan change address address varchar(20) null;

    create table score(
    id int primary key,
    sid int,
    zh int,
    en int,
    math int,
    constraint fk_sid foreign key(sid) references user(id)
    );

    insert into score values(1,2,45,56,34);
    insert into score values(2,1,88,90,120);

    alter table score drop foreign key fk_sid;
    mysql> update emp set dno =3 where eid=3;
    Query OK, 1 row affected (0.00 sec)
    Rows matched: 1 Changed: 1 Warnings: 0

    mysql> select * from emp;
    +-----+-------+--------+-----+
    | eid | ename | salaly | dno |
    +-----+-------+--------+-----+
    | 1 | 班长 | 10000 | 2 |
    | 2 | 美美 | 40000 | 1 |
    | 3 | 小凤 | 50000 | 3 |
    +-----+-------+--------+-----+
    3 rows in set (0.00 sec)

    mysql> desc emp;
    +--------+-------------+------+-----+---------+----------------+
    | Field | Type | Null | Key | Default | Extra |
    +--------+-------------+------+-----+---------+----------------+
    | eid | int(11) | NO | PRI | NULL | auto_increment |
    | ename | varchar(20) | YES | | NULL | |
    | salaly | double | YES | | NULL | |
    | dno | int(11) | NO | MUL | NULL | |
    +--------+-------------+------+-----+---------+----------------+
    4 rows in set (0.01 sec)

    mysql> delete from dept where did = 1;
    ERROR 1451 (23000): Cannot delete or update a parent row: a foreign key constrai
    nt fails (day16.emp, CONSTRAINT emp_ibfk_1 FOREIGN KEY (dno) REFERENCES
    dept (did))
    mysql>

    多表的查询

    笛卡尔积的概念:(了解)
        举个栗子
        
    表a             表b
    aid  aname      bid   bname
    a1    aa1       b1      bb1
    a2    aa2       b2      bb2
                    b3      bb3
    查询的语法
        select * from a,b;
    这么写返回的结果就是笛卡尔积
    a1    aa1       b1      bb1 
    a1    aa1       b2      bb2
    a1    aa1       b3      bb3
    
    a2    aa2       b1      bb1 
    a2    aa2       b2      bb2
    a2    aa2       b3      bb3
    这记过就是笛卡尔积  2*3 = 6条结果
    
    
    这就是多表查询啊哈哈哈哈
    select * from dept ,emp where dept.did=emp.eid;
     select * from dept inner join emp on dept.did=emp.eid && salaly = 10000;
    *多表查询
        * 内连接(用的比较多)
            * 普通内连接
                前提条件:需要有外键的
                关键字 inner join...on
                select * from dept inner join emp on dept.did=emp.eid;  
            * 隐式内连接(用的是最多的)
                select * from dept,emp where dept.did=emp.eid;
    
    
        *外连接
            左外连接
                select * from dept left outer join emp on dept.did=emp.eid;
                select * from dept left join emp on dept.did=emp.eid;
                    
        *右外连接
    
    
    insert into dept values(null,'呵呵部');
    insert into dept values(null,'卫生部');
    
    
    select * from dept;
    
    select * from dept left join emp on dept.did=emp.eid;
    
    select * from dept right join emp on dept.did=emp.eid;
    

    +--------+-------------+------+-----+---------+----------------+
    | Field | Type | Null | Key | Default | Extra |
    +--------+-------------+------+-----+---------+----------------+
    | eid | int(11) | NO | PRI | NULL | auto_increment |
    | ename | varchar(20) | YES | | NULL | |
    | salaly | double | YES | | NULL | |
    | dno | int(11) | NO | MUL | NULL | |
    +--------+-------------+------+-----+---------+----------------+

    insert into emp values(null,'呵呵部');
    insert into emp values(null,'马云',2565000000,null);
    insert into emp values(null,'马化腾',20000000000,null);
    insert into emp values(null,'马克龙',1000000000,null);
    insert into emp values(null,'马蓉',40000000,null);
    
    5 rows in set (0.00 sec)
    

    mysql> select * from dept left join emp on dept.did=emp.dno;
    +-----+--------+------+-------+------------+------+
    | did | dname | eid | ename | salaly | dno |
    +-----+--------+------+-------+------------+------+
    | 1 | 研发部 | 6 | 阿冷 | 40000 | 1 |
    | 2 | 销售部 | 1 | 马云 | 2565000000 | 2 |
    | 3 | 人事部 | 5 | 小凤 | 50000 | 3 |
    | 3 | 人事部 | 7 | 提莫 | 100000 | 3 |
    | 6 | 呵呵部 | NULL | NULL | NULL | NULL |
    | 7 | 卫生部 | NULL | NULL | NULL | NULL |
    +-----+--------+------+-------+------------+------+
    6 rows in set (0.00 sec)

    mysql> select * from dept right join emp on dept.did=emp.dno;
    +------+--------+-----+--------+-------------+------+
    | did | dname | eid | ename | salaly | dno |
    +------+--------+-----+--------+-------------+------+
    | 1 | 研发部 | 6 | 阿冷 | 40000 | 1 |
    | 2 | 销售部 | 1 | 马云 | 2565000000 | 2 |
    | 3 | 人事部 | 5 | 小凤 | 50000 | 3 |
    | 3 | 人事部 | 7 | 提莫 | 100000 | 3 |
    | NULL | NULL | 2 | 马化腾 | 20000000000 | NULL |
    | NULL | NULL | 3 | 马克龙 | 1000000000 | NULL |
    | NULL | NULL | 4 | 马蓉 | 40000000 | NULL |
    +------+--------+-----+--------+-------------+------+
    7 rows in set (0.00 sec)

    mysql>

    select * from dept,emp where dept.did = emp.dno;
    
    select d.dname,count(*) from dept d ,emp e where d.did = e.dno group by d.dname;

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