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os.path.join路径拼接

os.path.join路径拼接

作者: 可可酱X3 | 来源:发表于2020-05-25 17:34 被阅读0次

转自:https://www.cnblogs.com/an-ning0920/p/10037790.html

os.path.join()函数:连接两个或更多的路径名组件

                                1.如果各组件名首字母不包含’/’,则函数会自动加上

         2.如果有一个组件是一个绝对路径,则在它之前的所有组件均会被舍弃

         3.如果最后一个组件为空,则生成的路径以一个’/’分隔符结尾


Demo1

import os

Path1 = 'home'

Path2 = 'develop'

Path3 = 'code'

Path10 = Path1 + Path2 + Path3

Path20 = os.path.join(Path1,Path2,Path3)

print ('Path10 = ',Path10)

print ('Path20 = ',Path20)

输出

Path10 = homedevelopcode

Path20 = home\develop\code


Demo2

import os

Path1 = '/home'

Path2 = 'develop'

Path3 = 'code'

Path10 = Path1 + Path2 + Path3

Path20 = os.path.join(Path1,Path2,Path3)

print ('Path10 = ',Path10)

print ('Path20 = ',Path20)

输出

Path10 = /homedevelopcode

Path20 = /home\develop\code


Demo3

import os

Path1 = 'home'

Path2 = '/develop'

Path3 = 'code'

Path10 = Path1 + Path2 + Path3

Path20 = os.path.join(Path1,Path2,Path3)

print ('Path10 = ',Path10)

print ('Path20 = ',Path20)

输出

Path10 = home/developcode

Path20 = /develop\code


Demo4

import os

Path1 = 'home'

Path2 = 'develop'

Path3 = '/code'

Path10 = Path1 + Path2 + Path3

Path20 = os.path.join(Path1,Path2,Path3)

print ('Path10 = ',Path10)

print ('Path20 = ',Path20 )

输出

Path10 = homedevelop/code

Path20 = /code

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