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os.path.join路径拼接

os.path.join路径拼接

作者: 可可酱X3 | 来源:发表于2020-05-25 17:34 被阅读0次

    转自:https://www.cnblogs.com/an-ning0920/p/10037790.html

    os.path.join()函数:连接两个或更多的路径名组件

                                    1.如果各组件名首字母不包含’/’,则函数会自动加上

             2.如果有一个组件是一个绝对路径,则在它之前的所有组件均会被舍弃

             3.如果最后一个组件为空,则生成的路径以一个’/’分隔符结尾


    Demo1

    import os

    Path1 = 'home'

    Path2 = 'develop'

    Path3 = 'code'

    Path10 = Path1 + Path2 + Path3

    Path20 = os.path.join(Path1,Path2,Path3)

    print ('Path10 = ',Path10)

    print ('Path20 = ',Path20)

    输出

    Path10 = homedevelopcode

    Path20 = home\develop\code


    Demo2

    import os

    Path1 = '/home'

    Path2 = 'develop'

    Path3 = 'code'

    Path10 = Path1 + Path2 + Path3

    Path20 = os.path.join(Path1,Path2,Path3)

    print ('Path10 = ',Path10)

    print ('Path20 = ',Path20)

    输出

    Path10 = /homedevelopcode

    Path20 = /home\develop\code


    Demo3

    import os

    Path1 = 'home'

    Path2 = '/develop'

    Path3 = 'code'

    Path10 = Path1 + Path2 + Path3

    Path20 = os.path.join(Path1,Path2,Path3)

    print ('Path10 = ',Path10)

    print ('Path20 = ',Path20)

    输出

    Path10 = home/developcode

    Path20 = /develop\code


    Demo4

    import os

    Path1 = 'home'

    Path2 = 'develop'

    Path3 = '/code'

    Path10 = Path1 + Path2 + Path3

    Path20 = os.path.join(Path1,Path2,Path3)

    print ('Path10 = ',Path10)

    print ('Path20 = ',Path20 )

    输出

    Path10 = homedevelop/code

    Path20 = /code

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