题目分析
Given four lists A, B, C, D of integer values, compute how many tuples (i, j, k, l) there are such that A[i] + B[j] + C[k] + D[l] is zero.
To make problem a bit easier, all A, B, C, D have same length of N where 0 ≤ N ≤ 500. All integers are in the range of -228 to 228 - 1 and the result is guaranteed to be at most 231 - 1.
时间复杂度为 O(n ^ 2),空间复杂度为 O(n),解该题用到了 HashMap。
代码
class Solution {
public int fourSumCount(int[] A, int[] B, int[] C, int[] D) {
int res = 0;
Map<Integer, Integer> map = new HashMap<>();
for(int a : A) {
for(int b : B) {
int sum = a + b;
map.put(sum, map.getOrDefault(sum, 0) + 1);
}
}
for(int c : C) {
for(int d : D) {
int sum = -c - d;
res += map.getOrDefault(sum, 0);
}
}
return res;
}
}
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