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Ruby:Fizz Buzz

Ruby:Fizz Buzz

作者: Josaber | 来源:发表于2016-12-16 11:57 被阅读0次

来来来,让我们看一下

Write a program that outputs the string representation of numbers from 1 to n.
But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.

Example:

n = 15,

Return:
[ 
  "1", 
  "2", 
  "Fizz", 
  "4", 
  "Buzz", 
  "Fizz", 
  "7", 
  "8", 
  "Fizz", 
  "Buzz", 
  "11", 
  "Fizz", 
  "13", 
  "14", 
  "FizzBuzz"
]

题比较简单,输入一个数n返回1n之间的数,把能被3整除的替换为Fizz,能被5整除的替换为Buzz,能同时被35整除的数替换为FizzBuzz

写好了

def fizzBuzz(n)
    result = []
    for i in 1 .. n
        temp = i;
        if i % 3 == 0 then
            temp = "Fizz"
        end

        if i % 5 == 0 then
            if temp != i then
                temp += "Buzz"
            else
                temp = "Buzz"
            end
        end
        result << temp
    end
    return result
end

可以使用pp进行输出,详细代码见这里

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