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01 Two Sum

01 Two Sum

作者: 大李子biglee | 来源:发表于2017-11-14 21:33 被阅读0次
    Given an array of integers, return indices of the two numbers such that they add up to a specific target.
    
    You may assume that each input would have exactly one solution, and you may not use the same element twice.
    
    Example:
    Given nums = [2, 7, 11, 15], target = 9,
    
    Because nums[0] + nums[1] = 2 + 7 = 9,
    return [0, 1].
    
    
    class Solution(object):
        def twoSum(self, nums, target):
            nums1 = nums[:]
            nums1.sort()
            i = 0
            j = len(nums1) - 1 
            index = []
            while i < j:
                if nums1[i] + nums1[j] == target:
                    for x in range(len(nums)):
                        if nums[x] == nums1[i]:
                            index.append(x)
                            break
                    for x in range(len(nums)-1,-1,-1):
                        if nums[x] == nums1[j]:
                            index.append(x)
                            break
                    index.sort()
                    break
                elif nums1[i] + nums1[j] < target:
                    i += 1
                elif nums1[i] + nums1[j] > target:
                    j -= 1
            return index
    

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