函数导数解题路线图

作者: 7300T | 来源:发表于2019-04-07 19:22 被阅读50次
    函数导数解题路线图
    \include{fl_head}
    \begin{document}
    \begin{CJK}{UTF8}{gbsn}
    \include{fl}
    \begin{tikzpicture}[node distance=2cm]
    \node(pro1)[process]{函数导数解答题};
    \node(pro2)[process,right of=pro1,xshift=2cm]{分离};
    \node(pro3)[process,right of=pro2,xshift=2cm]{参变量分离};
    \node(pro4)[process,right of=pro3,xshift=2cm]{最值处理};
    \node(pro5)[process,below of=pro3]{函数分离};
    \node(pro6)[process,right of=pro5,xshift=2cm]{数形结合};
    \node(pro7)[process,below of=pro6]{分类讨论};
    \node(pro8)[process,below of=pro2,yshift=-4cm]{分离};
    \node(pro9)[process,below of=pro5,yshift=-2cm]{逻辑分解}; 
    \node(pro10)[process,below of=pro9]{过程分解};
    \node(pro11)[process,below of=pro10]{构造函数};
    \node(pro12)[process,right of=pro11,xshift=2cm]{变换主元};
    
    \node(pro13)[process,below of=pro12]{换元};
    \node(pro14)[process,below of=pro13]{作差(商)};
    \draw[arrow](pro1)--(pro2);
    \draw[arrow](pro2)--(pro3);
    \draw[arrow](pro3)--(pro4);
    \draw[arrow](pro2)|-(pro5);
    \draw[arrow](pro5)--(pro6);
    \draw[arrow](pro5)|-(pro7);
    \draw[arrow](pro1)|-(pro8);
    \draw[arrow](pro8)--(pro9);
    \draw[arrow](pro8)|-(pro10);
    \draw[arrow](pro8)|-(pro11);
    \draw[arrow](pro11)--(pro12);
    \draw[arrow](pro11)|-(pro13);
    \draw[arrow](pro11)|-(pro14);
    \end{tikzpicture}   
    \end{CJK}
        
    \end{document}
    
    

    用时44分钟。
    虽然用时长,但是有价值。

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        本文标题:函数导数解题路线图

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