美文网首页
正则式匹配

正则式匹配

作者: cde99bf0b5b1 | 来源:发表于2017-10-10 15:59 被阅读0次

    Implement regular expression matching with support for '.' and '*'.

    '.' Matches any single character.
    '*' Matches zero or more of the preceding element.

    The matching should cover the entire input string (not partial).

    The function prototype should be:
    bool isMatch(const char *s, const char *p)

    Some examples:
    isMatch("aa","a") → false
    isMatch("aa","aa") → true
    isMatch("aaa","aa") → false
    isMatch("aa", "a") → true
    isMatch("aa", ".
    ") → true
    isMatch("ab", ".") → true
    isMatch("aab", "c
    a*b") → true

    递归解法
    #include <string>
    using std::string;
    
    class Solution {
    public:
        bool isMatch(string s, string p) {
            if(p.empty()) return s.empty();
            
            if(p.size()<2)
                return !s.empty() && s.size() < 2 && (p[0] == s[0] || p[0] == '.');
            
            if(p[1] == '*')
                return isMatch(s, p.substr(2)) || !s.empty() && ((s[0] == p[0] || p[0] == '.') && isMatch(s.substr(1), p));
            else
                return !s.empty() && (s[0] == p[0] || p[0] == '.') && isMatch(s.substr(1), p.substr(1));
        }
    };
    

    相关文章

      网友评论

          本文标题:正则式匹配

          本文链接:https://www.haomeiwen.com/subject/pczvyxtx.html