在Java中比如想把一个数组转成集合,通常习惯使用Arrays.asList
,但是要小心,数组通过Arrays.asList
转成集合后,是不能调用集合的add,remove方法的.不然会抛异常UnsupportedOperationException
,
Demo
Integer[] array = {1, 2};
List<Object> list = Arrays.asList(array);
list.remove(1);
控制台结果
Exception in thread "main" java.lang.UnsupportedOperationException
at java.util.AbstractList.remove(AbstractList.java:161)
at com.study.webfluxstudy.ArrayListTest.main(ArrayListTest.java:19)
如果新人第一次碰到这个问题可能会感觉很奇怪,add,remove方法不应该是集合的标配吗,怎么会不支持呢?分析下底层源码就知道了
/**
* Returns a fixed-size list backed by the specified array.
*/
@SafeVarargs
@SuppressWarnings("varargs")
public static <T> List<T> asList(T... a) {
return new ArrayList<>(a);
}
Returns a fixed-size list backed by the specified array.
很关键的一句话,asList
返回的list是固定大小的,那也就是说生成后的集合就不能再添加删除了,也就是不能add
,remove
了.注释虽然是这么说,但是如果看方法体中的代码,return new ArrayList<>(a)
,是不是更奇怪了.ArrayList
大家在项目中常用的集合类,add
,remove
没问题啊.是什么原因呢?
阅读源码其实就能发现此ArrayList
不是彼ArrayList
.
asList
静态方法中的ArrayList
是Lists中的一个私有静态类,而不是java.util.ArrayList
private static class ArrayList<E> extends AbstractList<E>
implements RandomAccess, java.io.Serializable
{
private static final long serialVersionUID = -2764017481108945198L;
private final E[] a;
ArrayList(E[] array) {
a = Objects.requireNonNull(array);
}
@Override
public int size() {
return a.length;
}
@Override
public Object[] toArray() {
return a.clone();
}
@Override
@SuppressWarnings("unchecked")
public <T> T[] toArray(T[] a) {
int size = size();
if (a.length < size)
return Arrays.copyOf(this.a, size,
(Class<? extends T[]>) a.getClass());
System.arraycopy(this.a, 0, a, 0, size);
if (a.length > size)
a[size] = null;
return a;
}
@Override
public E get(int index) {
return a[index];
}
@Override
public E set(int index, E element) {
E oldValue = a[index];
a[index] = element;
return oldValue;
}
@Override
public int indexOf(Object o) {
E[] a = this.a;
if (o == null) {
for (int i = 0; i < a.length; i++)
if (a[i] == null)
return i;
} else {
for (int i = 0; i < a.length; i++)
if (o.equals(a[i]))
return i;
}
return -1;
}
@Override
public boolean contains(Object o) {
return indexOf(o) != -1;
}
@Override
public Spliterator<E> spliterator() {
return Spliterators.spliterator(a, Spliterator.ORDERED);
}
@Override
public void forEach(Consumer<? super E> action) {
Objects.requireNonNull(action);
for (E e : a) {
action.accept(e);
}
}
@Override
public void replaceAll(UnaryOperator<E> operator) {
Objects.requireNonNull(operator);
E[] a = this.a;
for (int i = 0; i < a.length; i++) {
a[i] = operator.apply(a[i]);
}
}
@Override
public void sort(Comparator<? super E> c) {
Arrays.sort(a, c);
}
}
public static int hashCode(long a[]) {
if (a == null)
return 0;
int result = 1;
for (long element : a) {
int elementHash = (int)(element ^ (element >>> 32));
result = 31 * result + elementHash;
}
return result;
}
通过上面的源码可以看到起没有提供add
,remove方法的实现
,那调用add
,remove
其实是调用父类的方法
AbstractList
public void add(int index, E element) {
throw new UnsupportedOperationException();
}
public E remove(int index) {
throw new UnsupportedOperationException();
}
所以也就能解释为什么Demo演示代码调用add
方法,在控制台会抛出UnsupportedOperationException
异常了
如果让Arrays.asList()
返回的集合支持add
,remove
方法
如果想实现这个目的需要借助java.util.ArrayList
帮忙
public ArrayList(Collection<? extends E> c) {
elementData = c.toArray();
if ((size = elementData.length) != 0) {
// c.toArray might (incorrectly) not return Object[] (see 6260652)
if (elementData.getClass() != Object[].class)
elementData = Arrays.copyOf(elementData, size, Object[].class);
} else {
// replace with empty array.
this.elementData = EMPTY_ELEMENTDATA;
}
}
调整后的Demo
Integer[] array = {1, 2};
// 通过Arrays转换成的List,保留了原本的类型
List<Integer> list = Arrays.asList(array);
System.out.println(list);
ArrayList<Integer> objects = new ArrayList<Integer>(list);
objects.add(3);
System.out.println(objects);
控制台输出
[1, 2]
[1, 2, 3]
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