leetcode_twoSum

作者: CodeRambler | 来源:发表于2018-12-14 16:07 被阅读4次

    题目

    LeetCode: two-sum

    two-sum

    暴力破解

    /**
     * Note: The returned array must be malloced, assume caller calls free().
     */
    int* twoSum(int* nums, int numsSize, int target) {
        int max = INT_MIN;
        int min = INT_MAX;
        int * indices = (int *) malloc(sizeof(int)*2);
        
        for (int i = 0; i < numsSize; ++i)
        {
            if (nums[i] > max) max = nums[i];
            if (nums[i] < min) min = nums[i];
        }
        int * map = (int *) calloc(max-min+1, sizeof(int));
        
        for (int i = 0; i < numsSize; ++i)
        {
            map[nums[i] - min] = i;
        }
        
        for (int i = 0; i < numsSize; ++i)
        {
            int lookfornum = target - nums[i];
            if (lookfornum < min || lookfornum > max) continue;
            if (map[lookfornum - min] != 0 && map[lookfornum - min] != i)
            {
                indices[0] = i;
                indices[1] = map[lookfornum - min];
                break;
            }
        }
        return indices;
    }
    

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