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前端ip地址校验

前端ip地址校验

作者: 泉泉泉泉泉泉 | 来源:发表于2019-07-15 23:26 被阅读0次
    var reg = "^(1\\d{2}|2[0-4]\\d|25[0-5]|[1-9]\\d|[1-9])\\."
    +"(1\\d{2}|2[0-4]\\d|25[0-5]|[1-9]\\d|\\d)\\."
    +"(1\\d{2}|2[0-4]\\d|25[0-5]|[1-9]\\d|\\d)\\."
    +"(1\\d{2}|2[0-4]\\d|25[0-5]|[1-9]\\d|\\d)$"
    //简化后
    var reg1 = '^(1\\d{2}|2[0-4]\\d|25[0-5]|[1-9]\\d|[1-9])(\\.(1\\d{2}|2[0-4]\\d|25[0-5]|[1-9]\\d|\\d)){3}$'
    // 此种写法有问题不能省略反斜杠
    var reg2 = '^(1\d{2}|2[0-4]\d|25[0-5]|[1-9]\d|[1-9])(\.(1\d{2}|2[0-4]\d|25[0-5]|[1-9]\d|\d)){3}$'
    console.log(reg)
    console.log(reg1)
    console.log(reg2)
    
    var pattern = new RegExp(reg)
    var pattern1 = new RegExp(reg1)
    var pattern2 = new RegExp(reg2)
    
    var ip = '127.0.0.1';
    console.log(pattern.test(ip))
    console.log(pattern1.test(ip))
    console.log(pattern2.test(ip))
    

    结果

    true
    true
    false
    

    参考博客:https://blog.csdn.net/u012806692/article/details/50635590

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