61 Search For A Range
作者:
博瑜 | 来源:发表于
2017-06-27 08:33 被阅读0次public class Solution {
/**
*@param A : an integer sorted array
*@param target : an integer to be inserted
*return : a list of length 2, [index1, index2]
*/
public int[] searchRange(int[] A, int target) {
// write your code here
int[] result = new int[2];
result[0] = -1;
result[1] = -1;
if (A == null) return result;
int length = A.length;
if (length == 0) return result;
int start = 0;
int end = length - 1;
while (start + 1 < end) {
int mid = start + (end - start) / 2;
if (A[mid] == target) end = mid;
else if (A[mid] > target) end = mid;
else start = mid;
}
if (A[start] == target) result[0] = start;
else if (A[end] == target) result[0] = end;
else return result;
start = 0;
end = length - 1;
while (start + 1 < end) {
int mid = start + (end - start) / 2;
if (A[mid] == target) start = mid;
else if (A[mid] > target) end = mid;
else start = mid;
}
if (A[end] == target) result[1] = end;
else result[1] = start;
return result;
}
}
本文标题:61 Search For A Range
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