ios用post请求xml数据

这几天做东西用到了post请求xml数据，然后整理了一下。

1 创建一个类

#import<Foundation/Foundation.h>

@interface MYXml : NSObject

- (void)MYXml:(NSDictionary*)params :(void(^)(NSDictionary*resultDic))result;

@end

#import "MYXml.h"

@implementation JYDPaySDK

-(void)MYXml:(NSDictionary *)params :(void (^)(NSDictionary *))result{    NSString *urlString =JYDURL;    NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];    [request setURL:[NSURL URLWithString:urlString]];    [request setHTTPMethod:@"POST"];    NSString *contentType = [NSString stringWithFormat:@"text/xml"];    [request addValue:contentType forHTTPHeaderField: @"Content-Type"];    NSMutableData *postBody = [NSMutableData data];    [postBody appendData:[[NSString stringWithFormat:@""] dataUsingEncoding:NSUTF8StringEncoding]];    [postBody appendData:[[NSString stringWithFormat:@"%@",params[@"service"]] dataUsingEncoding:NSUTF8StringEncoding]];    [postBody appendData:[[NSString stringWithFormat:@"%@",params[@"version"]] dataUsingEncoding:NSUTF8StringEncoding]];

[postBody appendData:[[NSString stringWithFormat:@""] dataUsingEncoding:NSUTF8StringEncoding]];

[request setHTTPBody:postBody];

NSHTTPURLResponse* urlResponse = nil;

NSError *error = [[NSError alloc] init];

NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:&error];

if ([urlResponse statusCode] >= 200 && [urlResponse statusCode] < 300) {

得到返回结果，如果是xml格式，使用这个XMLReader github.com/amarcadet/XMLReader是非常不错的选择

}

@end