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Day15 剑指offer:反转链表

Day15 剑指offer:反转链表

作者: zheng7 | 来源:发表于2017-08-10 15:50 被阅读0次

输入一个链表,反转链表后,输出链表的所有元素。

/*
public class ListNode {
    int val;
    ListNode next = null;

    ListNode(int val) {
        this.val = val;
    }
}*/
public class Solution {
    public ListNode ReverseList(ListNode head) {
        if(head == null) return null;
        if(head.next == null) return head;
        ListNode res = head;
        ListNode nextHead = head.next;
        ListNode node;
        head.next = null;
        while(nextHead.next != null){
            node = nextHead.next;
            nextHead.next = res;
            res = nextHead;
            nextHead = node;
        }
        nextHead.next = res;
        res = nextHead;
        return res;
    }
}

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