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JPA findBy关键字列表

JPA findBy关键字列表

作者: lew1sss | 来源:发表于2019-07-17 16:12 被阅读0次

由于对JPA并不太了解,最近在学习中。

总结一下findBy关键字使用方法。

关键字列表

关键字 示例 JPQL表达
And findByLastnameAndFirstname ... where x.lastname = ?1 and x.firstname = ?2
Or findByLastnameOrFirstname ... where x.lastname = ?1 or x.firstname = ?2
Is、Equals findByFirstname、<br />findByFirstnameIs、<br />findByFirstnameEquals ... where x.firstname = ?1
Between findByStartDateBetween ... where x.startDate between ?1 and ?2
LessThan findByAgeLessThan ... where x.age < ?1
LessThanEquals findByAgeLessThanEqual ... where x.age <= ?1
GreaterThan findByAgeGreaterThan ... where x.age > ?1
GreaterThanEquals findByAgeGreaterThanEquals ... where x.age >= ?1
After findByStartAfter ... where x.startDate > ?1
Before findByStartBefore ... where x.startDate < ?1
IsNull findByAgeIsNull ... where x.age is null
IsNotNull,<br />NotNull findByAge(Is)NotNull ... where x.age not null
Like findByFirstnameLike ... where x.firstname like ?1
NotLike findByFirstnameNotLike ... where x.firstname not like ?1
StartingWith findByFirstnameStartingWith ... where x.firstname like ?1(参数增加前缀%)
EndingWith findByFirstnameEndingWith ... where x.firstname like ?1(参数增加后缀%)
Containing findByFirstnameContaining ... where x.firstname like ?1(参数被%包裹)
OrderBy findByAgeOrderByLastnameDesc ... where x.age = ?1 order by x.lastname desc
Not findByLastnameNot ... where x.lastname <> ?1
In findByAgeIn(Collection<Age> ages) ... where x.age in ?1
NotIn findByAgeNotIn(Collection<Age> ages) ... where x.age not in ?1
True findByActiveTrue() ... where x.active = true
False findByActiveFalse() ... where x.active = false
Ignore findByFirstnameIgnoreCase ... where UPPER(x.firstname) = UPPER(?1)

除了find前缀之外,还有read、get、query、stream

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