tag:
- Medium;
question:
A character in UTF8 can be from 1 to 4 bytes long, subjected to the following rules:
- For 1-byte character, the first bit is a 0, followed by its unicode code.
- For n-bytes character, the first n-bits are all one's, the n+1 bit is 0, followed by n-1 bytes with most significant 2 bits being 10.
This is how the UTF-8 encoding would work:
Char. number range | UTF-8 octet sequence
(hexadecimal) | (binary)
--------------------+---------------------------------------------
0000 0000-0000 007F | 0xxxxxxx
0000 0080-0000 07FF | 110xxxxx 10xxxxxx
0000 0800-0000 FFFF | 1110xxxx 10xxxxxx 10xxxxxx
0001 0000-0010 FFFF | 11110xxx 10xxxxxx 10xxxxxx 10xxxxxx
Given an array of integers representing the data, return whether it is a valid utf-8 encoding.
Note:
The input is an array of integers. Only the least significant 8 bits of each integer is used to store the data. This means each integer represents only 1 byte of data.
Example 1:
data = [197, 130, 1], which represents the octet sequence: 11000101 10000010 00000001.
Return true.
It is a valid utf-8 encoding for a 2-bytes character followed by a 1-byte character.
Example 2:
data = [235, 140, 4], which represented the octet sequence: 11101011 10001100 00000100.
Return false.
The first 3 bits are all one's and the 4th bit is 0 means it is a 3-bytes character.
The next byte is a continuation byte which starts with 10 and that's correct.
But the second continuation byte does not start with 10, so it is invalid.
思路:
每次只检测每个编码的第一个字节,根据上面的规则,判断它有几个字节构成,然后检测后面剩余的字节是否以“10”打头。
class Solution {
public:
bool validUtf8(vector<int>& data) {
int dataSize = data.size();
int index = 0;
while (index < dataSize){
int tempValue = data[index] >> 3;
if (tempValue == 30) {//当正在检测的字节显示“11110” == 30,说明这是一个有四个字节长度的编码
if (index + 3 < dataSize && (data[index + 1] >> 6) == 2 && (data[index + 2] >> 6) == 2 && (data[index + 3] >> 6) == 2){
index += 4;
continue;
}
else return false;
}
tempValue >>= 1;
if (tempValue == 14) {//当正在检测的字节显示“1110” == 14,说明这是一个有三个字节长度的编码
if (index + 2 < dataSize && (data[index + 1] >> 6) == 2 && (data[index + 2] >> 6) == 2){
index += 3;
continue;
}
else return false;
}
tempValue >>= 1;
if (tempValue == 6) {//当正在检测的字节显示“110” == 6,说明这是一个有两个字节长度的编码
if (index + 1 < dataSize && (data[index + 1] >> 6) == 2){
index += 2;
continue;
}
else return false;
}
tempValue >>= 2;
if (tempValue == 0) {//当正在检测的字节显示“0” == 0,说明这是一个只有一个字节长度的编码
index += 1;
}
else return false;
}
return true;
}
};
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