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valueForKeyPath

valueForKeyPath

作者: WhistleCai | 来源:发表于2018-11-15 11:17 被阅读0次
      - (nullable id)valueForKeyPath:(NSString *)keyPath;
    

    1. 数组求和

    如果一个数组是由NSNumber或者数字的字符串组成的,可以直接进行进行求和:

    NSArray *array = @[@13, @23, @89, @3, @4, @46, @"2"];
    CGFloat sum1 = [[array valueForKeyPath:@"@sum.floatValue"] floatValue];
    NSLog(@"%f", sum1); // 180
    
    NSArray *array5 = @[@"3", @"4", @"10"];
    CGFloat sum2 = [[array5 valueForKeyPath:@"@sum.floatValue"] floatValue];
    NSLog(@"%f", sum2);   //17
    

    2. 数组内字符串操作

    如果一个数组是由字符串组成的,那么字符串有的属性,都可以直接对数组内所有的字符串统一进行操作,例如:uppercaseString: 全部大写

    NSArray *array = @[@"aa", @"bb", @"cc"];
        
    NSArray *tmp = [array valueForKeyPath:@"uppercaseString"];
        
    NSLog(@"%@", tmp);
    /*
    (
        AA,
        BB,
        CC
    )
    */
    

    length: 获取每个字符串长度

    NSArray *array = @[@"aa", @"bb", @"cc"];
    NSArray *lengths = [array valueForKeyPath:@"length"];
    NSLog(@"%@", lengths);
    /*
    (
        2,
        2,
        2
    )
    */
    

    3. 对数组内的字典相同的key取值

    如果数组内包含的对象是字典,那么可以直接取出某个key的所有值:

    NSArray *array1 = @[
      @{@"uid": @"id001", @"info":@{@"owner": @"zhanSan", @"code":@"001"}},
      @{@"uid": @"id002", @"info":@{@"owner": @"liSi", @"code":@"002"}},
      @{@"uid": @"id003", @"info":@{@"owner": @"wangEr", @"code":@"003"}}
      ];
        
    NSArray *uids = [array1 valueForKeyPath:@"uid"];
    /*(
        id001,
        id002,
        id003
    )
    */
    

    4. 数组去重

    如果数组内包含重复的元素,可以直接去重:

    NSArray *array2 = @[@"1", @"dd", @"ccc", @"dd", @"1", @"d", @"d"];
    NSArray *rs = [array2 valueForKeyPath:@"@distinctUnionOfObjects.self"];
    NSLog(@"%@", rs);
    /*(
        dd,
        d,
        1,
        ccc
    )
    */
    

    5. 数组内包含字典,去重字典某字段的重复值

    如果数组中包含字典,字典某些字段的值是重复的,那么可以直接取出去掉了重复值的内容:

    NSArray *array3 = @[
                            @{@"name": @"zhangsan", @"age": @"1"},
                            @{@"name": @"zhangsan", @"age": @"1"},
                            @{@"name": @"lisi", @"age": @"2"}
                            ];
        
    NSArray * arr = [array3 valueForKeyPath:@"@distinctUnionOfObjects.name"];
    NSLog(@"%@", arr);
    /*(
        zhangsan,
        lisi
    )
    */
    

    6. 多级字典嵌套取值

    如果字典中包含很多层字典,可以很方便的取出最内层字典的某个值:

    NSDictionary *dic = @{
                              @"key1": @{
                                      @"key2": @{
                                              @"key3": @"lisi002"
                                              }
                                      }
                              };
    NSString *key = [dic valueForKeyPath:@"key1.key2.key3"];
    
    NSLog(@"%@", key);
     // lisi002
    

    7. 数组内模型取值

    如果数组内存放的是数据模型,同样可以取出其中某个属性的值:

    NSArray *array = @[@"aa", @"bb", @"cc"];
        
        NSMutableArray *peoples = [NSMutableArray arrayWithCapacity:array.count];
        for (int i = 0; i < array.count; i++) {
            People *p = [[People alloc]init];
            p.name = array[i];
            p.age = i;
            [peoples addObject:p];
        }
        
        NSArray *names = [peoples valueForKeyPath:@"name"];
        NSLog(@"%@", names);
    /*(
        aa,
        bb,
        cc
    )
    */
    

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