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从请求JSON中构建ES的SearchSourceBuilder

从请求JSON中构建ES的SearchSourceBuilder

作者: Cheava | 来源:发表于2020-03-02 11:02 被阅读0次
String query = "..."
SearchSourceBuilder searchSourceBuilder = new SearchSourceBuilder();
SearchModule searchModule = new SearchModule(Settings.EMPTY, false, Collections.emptyList());
try (XContentParser parser = XContentFactory.xContent(XContentType.JSON).createParser(new NamedXContentRegistry(searchModule
            .getNamedXContents()), query)) {
    searchSourceBuilder.parseXContent(parser);
}

将请求json放到以上代码中,并通过debug模式查看构建好的searchSourceBuilder,查看构建需要哪些builder以及之间的层级关系,最后通过searchSourceBuilder.source()看下请求json是否符合原json

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