原题链接：Same Tree
class Solution:
# @param {TreeNode} p
# @param {TreeNode} q
# @return {boolean}
def isSameTree(self, p, q):
if p is None and q is None:
return True
elif p is None or q is None:
return False
else:
if p.val == q.val:
return self.isSameTree(p.left, q.left) and self.isSameTree(p.right, q.right)
return False
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原题链接：Same Tree
类似symmetric tree判断，只有满足两个数都不是NULL，而且保存值相同，L=L R=R
100. Same Tree Description Given two binary trees, write ...
100. Same Tree[思路] 二叉树匹配
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本文标题：100 Same Tree
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