美文网首页编程
Python基础学习5

Python基础学习5

作者: ericblue | 来源:发表于2018-11-28 13:10 被阅读0次

    函数学习要点:
    1、函数基本操作:调用、创建、可变长参数(在方法定义中可以使用个数不确定的参数,不按顺序传参用关键字,不固定参数个数定义为fun(first,*other))、变量作用域
    2、匿名函数(Lambda函数)
    3、函数迭代器、生成器
    4、函数闭包、装饰器
    5、内建函数
    6、自定义上下文管理器
    实践操作代码:
    未使用函数时代码

    # 读取人物名称,name.txt是创建在代码路径下人物txt文档
    f = open('name.txt',encoding='utf-8')
    data = f.read()
    data0 = data.split('|')
    print(type(data))
    print(data0)
    
    # 读取兵器名称,weapon.txt是创建在代码路径下兵器txt文档
    f2 = open('weapon.txt',encoding='utf-8')
    i = 1
    for  line in f2.readlines():
        if i % 2 == 1:
            print(line.strip('\n'))
        i += 1
    
    # 去掉文件中每行文字换行,sanguo_utf8.txt是创建在代码路径下文章txt文档
    f3 = open('sanguo_utf8.txt',encoding='utf-8')
    print(f3.read().replace('\n',''))
    

    上面功能用函数实现代码

    def func(filename):
        print(open(filename,encoding='utf-8').read())
        print('test func')
    
    func('name.txt')
    

    用函数实现统计人物和武器出现次数例子

    import re
    
    def find_main_charecters(charecter_name):
        with open('sanguo_utf8.txt', encoding='utf-8') as f:
            data = f.read().replace("\n", "")
            name_num = re.findall(charecter_name, data)
            # print('主角 %s 出现了%s 次'%(charecter_name,len(name_num)))
        return charecter_name, len(name_num)
    
    
    name_dict = {}
    with open('name.txt', encoding='utf-8') as f:
        for line in f:
            names = line.split('|')
            for n in names:
                char_name, char_number = find_main_charecters(n)
                name_dict[char_name] = char_number
    
    weapon_dict = {}
    with open('weapon.txt', encoding='utf-8') as f:
            i = 1
            for line in f:
                 if i%2 == 1:
                    weapon_name, weapon_number = find_main_charecters(line.strip())
                    weapon_dict[weapon_name] = weapon_number
                 i = i+1
    
    
    name_sorted = sorted(name_dict.items(), key=lambda item: item[1], reverse=True)
    print(name_sorted[0:10])
    
    weapon_sorted = sorted(weapon_dict.items(), key=lambda item: item[1], reverse=True)
    print(weapon_sorted[0:10])
    

    函数可变长参数例子

    # #取得参数的个数
    def  howlong(first, *other):
        print( 1 + len(other))
    
    howlong(55,66,77)
    

    函数迭代器、生成器

    # iter() next()
    
    list1 =[1, 2, 3]
    it = iter(list1)
    print( next(it))
    print( next(it))
    print( next(it))
    print( next(it)) # except:StopIteration
    
    #yield
    def frange(start, stop, step):
        x = start
        while x < stop:
            yield x
            x += step
    
    for i in frange(10,20,0.5):
        print(i)
    

    Lambda表达式

    def true():return True
    lambda : True
    
    def add(x,y): return x+y
    add2 = lambda x,y : x+y
    print(add2(5,6))
    
    def testfunc(a_num): def testfunc(a_num):return a_num +1
    var = lambda b_num : b_num + 1 
    print(var(5))
    

    相关文章

      网友评论

        本文标题:Python基础学习5

        本文链接:https://www.haomeiwen.com/subject/rvzpqqtx.html