/*
Count the number of segments in a string, where a segment is defined to be a contiguous sequence of non-space characters.
Please note that the string does not contain any non-printable characters.
Example:
Input: "Hello, my name is John"
Output: 5
*/
/*
Thinking:
1. 要考虑头尾空格的问题
2. 要考虑没有空格的问题
3. 要考虑中间多个空格的问题
综合以上如果
空格即为比较元素,字符串对于分割体来说,只存在两种元素,
非空格,空格
_----_----__-----
符合这种0,1信号的问题,从0到1算作一个section,1降到0不计入,
也可以理解为波峰波谷之间的关系抽象
*/
enum SecmentsStatus: String {
case Space = " "
case Other = "o"
//切换状态,返回是否切换
mutating func switchStatus(_ str: String) -> Bool {
//把输入的子串转换对两种模式
let covertStr = (str == SecmentsStatus.Space.rawValue) ? SecmentsStatus.Space : SecmentsStatus.Other
//与当前状态相同,则不做改变
if covertStr == self { //相同直接返回,不做改变
return false
}
//不同,则做切换
switch self {
case .Space:
self = SecmentsStatus.Other
return true
case .Other:
self = SecmentsStatus.Space
return false
}
}
}
func secments(In str: String) -> Int {
var beforeCharacter = SecmentsStatus.Space
var count = 0
for character in str.characters {
//发生了切换则+1
if beforeCharacter.switchStatus(String(character)) {
count += 1
}
}
return count
}
secments(In: "")
secments(In: "ab")
secments(In: "ab cd")
secments(In: "cd ef, defgh")
secments(In: "abc, def")
网友评论