题目:
给定一个 Weather 表,编写一个 SQL 查询,来查找与之前(昨天的)日期相比温度更高的所有日期的 Id。
+---------+------------------+------------------+
| Id(INT) | RecordDate(DATE) | Temperature(INT) |
+---------+------------------+------------------+
| 1 | 2015-01-01 | 10 |
| 2 | 2015-01-02 | 25 |
| 3 | 2015-01-03 | 20 |
| 4 | 2015-01-04 | 30 |
+---------+------------------+------------------+
例如,根据上述给定的 Weather 表格,返回如下 Id:
+----+
| Id |
+----+
| 2 |
| 4 |
+----+
链接:https://leetcode-cn.com/problems/rising-temperature
思路:
1、这题主要考察SQL中的datediff函数
SQL如下:
select A.Id
from Weather A
left join Weather B
on datediff(A.RecordDate, B.RecordDate)=1
where B.RecordDate is not null
and A.Temperature>B.Temperature
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